day1/session4.tex
author Nishanth Amuluru <nishanth@fossee.in>
Tue, 14 Dec 2010 23:15:36 +0530
branchscipyin2010
changeset 456 a27ccfc118fb
parent 448 dc8d666a594a
permissions -rw-r--r--
removed sslc1.txt from circulate since it is not required

%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
%Tutorial slides on Python.
%
% Author: FOSSEE
% Copyright (c) 2009, FOSSEE, IIT Bombay
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% Title page
\title[Solving Equations \& ODEs]{Python for Science and Engg:\\SciPy}

\author[FOSSEE] {FOSSEE}

\institute[IIT Bombay] {Department of Aerospace Engineering\\IIT Bombay}
\date[] {SciPy.in 2010, Tutorials}
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%% Delete this, if you do not want the table of contents to pop up at
%% the beginning of each subsection:
\AtBeginSubsection[]
{
  \begin{frame}<beamer>
    \frametitle{Outline}
    \tableofcontents[currentsection,currentsubsection]
  \end{frame}
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    \frametitle{Outline}
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\begin{document}

\begin{frame}
  \maketitle
\end{frame}

%% \begin{frame}
%%   \frametitle{Outline}
%%   \tableofcontents
%%   % You might wish to add the option [pausesections]
%% \end{frame}

\section{Least Squares Fit}
\begin{frame}[fragile]
\frametitle{$L$ vs. $T^2$ - Scatter}
Linear trend visible.
\vspace{-0.1in}
\begin{figure}
\includegraphics[width=4in]{data/L-Tsq-points}
\end{figure}
\end{frame}

\begin{frame}[fragile]
\frametitle{$L$ vs. $T^2$ - Line}
This line does not make any mathematical sense.
\vspace{-0.1in}
\begin{figure}
\includegraphics[width=4in]{data/L-Tsq-Line}
\end{figure}
\end{frame}

\begin{frame}[fragile]
\frametitle{$L$ vs. $T^2$ - Least Square Fit}
This is what our intention is.
\vspace{-0.1in}
\begin{figure}
\includegraphics[width=4in]{data/least-sq-fit}
\end{figure}
\end{frame}

\begin{frame}[fragile]
\frametitle{Matrix Formulation}
\begin{itemize}
\item We need to fit a line through points for the equation $T^2 = m \cdot L+c$
\item In matrix form, the equation can be represented as $T_{sq} = A \cdot p$, where $T_{sq}$ is
  $\begin{bmatrix}
  T^2_1 \\
  T^2_2 \\
  \vdots\\
  T^2_N \\
  \end{bmatrix}$
, A is   
  $\begin{bmatrix}
  L_1 & 1 \\
  L_2 & 1 \\
  \vdots & \vdots\\
  L_N & 1 \\
  \end{bmatrix}$
  and p is 
  $\begin{bmatrix}
  m\\
  c\\
  \end{bmatrix}$
\item We need to find $p$ to plot the line
\end{itemize}
\end{frame}

\begin{frame}[fragile]
\frametitle{Getting $L$ and $T^2$}
%If you \alert{closed} IPython after session 2
\begin{lstlisting}
In []: L, T = loadtxt('pendulum.txt', 
                      unpack=True)
In []: tsq = T*T
\end{lstlisting}
\end{frame}

\begin{frame}[fragile]
\frametitle{Generating $A$}
\begin{lstlisting}
In []: A = array([L, ones_like(L)])
In []: A = A.T
\end{lstlisting}
\end{frame}

\begin{frame}[fragile]
\frametitle{\typ{lstsq} \ldots}
\begin{itemize}
\item Now use the \typ{lstsq} function
\item Along with a lot of things, it returns the least squares solution
\end{itemize}
\begin{lstlisting}
In []: result = lstsq(A,tsq)
In []: coef = result[0]
\end{lstlisting}
\end{frame}

\begin{frame}[fragile]
\frametitle{Least Square Fit Line \ldots}
We get the points of the line from \typ{coef}
\begin{lstlisting}
In []: Tline = coef[0]*L + coef[1]

In []: Tline.shape
\end{lstlisting}
\begin{itemize}
\item Now plot \typ{Tline} vs. \typ{L}, to get the Least squares fit line. 
\end{itemize}
\begin{lstlisting}
In []: plot(L, Tline, 'r')

In []: plot(L, tsq, 'o')
\end{lstlisting}
\end{frame}

\begin{frame}[fragile]
\frametitle{Least Squares Fit}
\vspace{-0.15in}
\begin{figure}
\includegraphics[width=4in]{data/least-sq-fit}
\end{figure}
\end{frame}

\section{Solving linear equations}

\begin{frame}[fragile]
\frametitle{Solution of equations}
Consider,
  \begin{align*}
    3x + 2y - z  & = 1 \\
    2x - 2y + 4z  & = -2 \\
    -x + \frac{1}{2}y -z & = 0
  \end{align*}
Solution:
  \begin{align*}
    x & = 1 \\
    y & = -2 \\
    z & = -2
  \end{align*}
\end{frame}

\begin{frame}[fragile]
\frametitle{Solving using Matrices}
Let us now look at how to solve this using \kwrd{matrices}
  \begin{lstlisting}
In []: A = array([[3,2,-1],
                  [2,-2,4],                   
                  [-1, 0.5, -1]])
In []: b = array([1, -2, 0])
In []: x = solve(A, b)
  \end{lstlisting}
\end{frame}

\begin{frame}[fragile]
\frametitle{Solution:}
\begin{lstlisting}
In []: x
Out[]: array([ 1., -2., -2.])
\end{lstlisting}
\end{frame}

\begin{frame}[fragile]
\frametitle{Let's check!}
\begin{small}
\begin{lstlisting}
In []: Ax = dot(A, x)
In []: Ax
Out[]: array([  1.00000000e+00,  -2.00000000e+00,  -1.11022302e-16])
\end{lstlisting}
\end{small}
\begin{block}{}
The last term in the matrix is actually \alert{0}!\\
We can use \kwrd{allclose()} to check.
\end{block}
\begin{lstlisting}
In []: allclose(Ax, b)
Out[]: True
\end{lstlisting}
\inctime{10}
\end{frame}

\begin{frame}[fragile]
\frametitle{Problem}
Solve the set of equations:
\begin{align*}
  x + y + 2z -w & = 3\\
  2x + 5y - z - 9w & = -3\\
  2x + y -z + 3w & = -11 \\
  x - 3y + 2z + 7w & = -5\\
\end{align*}
\inctime{5}
\end{frame}

\begin{frame}[fragile]
\frametitle{Solution}
Use \kwrd{solve()}
\begin{align*}
  x & = -5\\
  y & = 2\\
  z & = 3\\
  w & = 0\\
\end{align*}
\end{frame}

\section{Finding Roots}

\begin{frame}[fragile]
\frametitle{SciPy: \typ{roots}}
\begin{itemize}
\item Calculates the roots of polynomials
\item To calculate the roots of $x^2-5x+6$ 
\end{itemize}
\begin{lstlisting}
  In []: coeffs = [1, -5, 6]
  In []: roots(coeffs)
  Out[]: array([3., 2.])
\end{lstlisting}
\vspace*{-.2in}
\begin{center}
\includegraphics[height=1.6in, interpolate=true]{data/roots}    
\end{center}
\end{frame}

\begin{frame}[fragile]
\frametitle{SciPy: \typ{fsolve}}
\begin{small}
\begin{lstlisting}
  In []: from scipy.optimize import fsolve
\end{lstlisting}
\end{small}
\begin{itemize}
\item Finds the roots of a system of non-linear equations
\item Input arguments - Function and initial estimate
\item Returns the solution
\end{itemize}
\end{frame}

\begin{frame}[fragile]
\frametitle{\typ{fsolve}}
Find the root of $sin(z)+cos^2(z)$ nearest to $0$
\vspace{-0.1in}
\begin{center}
\includegraphics[height=2.8in, interpolate=true]{data/fsolve}    
\end{center}
\end{frame}

\begin{frame}[fragile]
\frametitle{\typ{fsolve}}
Root of $sin(z)+cos^2(z)$ nearest to $0$
\begin{lstlisting}
In []: fsolve(sin(z)+cos(z)*cos(z), 0)
NameError: name 'z' is not defined
\end{lstlisting}
\end{frame}

\begin{frame}[fragile]
\frametitle{\typ{fsolve}}
\begin{lstlisting}
In []: z = linspace(-pi, pi)
In []: fsolve(sin(z)+cos(z)*cos(z), 0)
\end{lstlisting}
\begin{small}
\alert{\typ{TypeError:}}
\typ{'numpy.ndarray' object is not callable}
\end{small}
\end{frame}

\begin{frame}[fragile]
\frametitle{Functions - Definition}
We have been using them all along. Now let's see how to define them.
\begin{lstlisting}
In []: def g(z):
 ....:     return sin(z)+cos(z)*cos(z)
\end{lstlisting}
\begin{itemize}
\item \typ{def} -- keyword
\item name: \typ{g}
\item arguments: \typ{z}
\item \typ{return} -- keyword
\end{itemize}
\end{frame}

\begin{frame}[fragile]
\frametitle{Functions - Calling them}
\begin{lstlisting}
In []: g()
---------------------------------------
\end{lstlisting}
\alert{\typ{TypeError:}}\typ{g() takes exactly 1 argument}
\typ{(0 given)}
\begin{lstlisting}
In []: g(0)
Out[]: 1.0
In []: g(1)
Out[]: 1.1333975665343254
\end{lstlisting}
More on Functions later \ldots
\end{frame}

\begin{frame}[fragile]
\frametitle{\typ{fsolve} \ldots}
Find the root of $sin(z)+cos^2(z)$ nearest to $0$
\begin{lstlisting}
In []: fsolve(g, 0)
Out[]: -0.66623943249251527
\end{lstlisting}
\begin{center}
\includegraphics[height=2in, interpolate=true]{data/fsolve}    
\end{center}
\end{frame}

\begin{frame}[fragile]
  \frametitle{Exercise Problem}
  Find the root of the equation $x^2 - sin(x) + cos^2(x) = tan(x)$ nearest to $0$
\end{frame}

\begin{frame}[fragile]
  \frametitle{Solution}
  \begin{small}
  \begin{lstlisting}
def g(x):
    return x**2 - sin(x) + cos(x)*cos(x) - tan(x)
fsolve(g, 0)
  \end{lstlisting}
  \end{small}
  \begin{center}
\includegraphics[height=2in, interpolate=true]{data/fsolve_tanx}
  \end{center}
\end{frame}

%% \begin{frame}[fragile]
%% \frametitle{Scipy Methods \dots}
%% \begin{small}
%% \begin{lstlisting}
%% In []: from scipy.optimize import fixed_point

%% In []: from scipy.optimize import bisect

%% In []: from scipy.optimize import newton
%% \end{lstlisting}
%% \end{small}
%% \end{frame}

\section{ODEs}

\begin{frame}[fragile]
\frametitle{Solving ODEs using SciPy}
\begin{itemize}
\item Consider the spread of an epidemic in a population
\item $\frac{dy}{dt} = ky(L-y)$ gives the spread of the disease
\item $L$ is the total population.
\item Use $L = 2.5E5, k = 3E-5, y(0) = 250$
\item Define a function as below
\end{itemize}
\begin{lstlisting}
In []: from scipy.integrate import odeint
In []: def epid(y, t):
  ....     k = 3.0e-5
  ....     L = 2.5e5
  ....     return k*y*(L-y)
  ....
\end{lstlisting}
\end{frame}

\begin{frame}[fragile]
\frametitle{Solving ODEs using SciPy \ldots}
\begin{lstlisting}
In []: t = linspace(0, 12, 61)

In []: y = odeint(epid, 250, t)

In []: plot(t, y)
\end{lstlisting}
%Insert Plot
\end{frame}

\begin{frame}[fragile]
\frametitle{Result}
\begin{center}
\includegraphics[height=2in, interpolate=true]{data/image}  
\end{center}
\end{frame}


\begin{frame}[fragile]
\frametitle{ODEs - Simple Pendulum}
We shall use the simple ODE of a simple pendulum. 
\begin{equation*}
\ddot{\theta} = -\frac{g}{L}sin(\theta)
\end{equation*}
\begin{itemize}
\item This equation can be written as a system of two first order ODEs
\end{itemize}
\begin{align}
\dot{\theta} &= \omega \\
\dot{\omega} &= -\frac{g}{L}sin(\theta) \\
 \text{At}\ t &= 0 : \nonumber \\
 \theta = \theta_0(10^o)\quad & \&\quad  \omega = 0\ (Initial\ values)\nonumber 
\end{align}
\end{frame}

\begin{frame}[fragile]
\frametitle{ODEs - Simple Pendulum \ldots}
\begin{itemize}
\item Use \typ{odeint} to do the integration
\end{itemize}
\begin{lstlisting}
In []: def pend_int(initial, t):
  ....     theta = initial[0]
  ....     omega = initial[1]
  ....     g = 9.81
  ....     L = 0.2
  ....     F=[omega, -(g/L)*sin(theta)]
  ....     return F
  ....
\end{lstlisting}
\end{frame}

\begin{frame}[fragile]
\frametitle{ODEs - Simple Pendulum \ldots}
\begin{itemize}
\item \typ{t} is the time variable \\ 
\item \typ{initial} has the initial values
\end{itemize}
\begin{lstlisting}
In []: t = linspace(0, 20, 101)
In []: initial = [10*2*pi/360, 0]
\end{lstlisting} 
\end{frame}

\begin{frame}[fragile]
\frametitle{ODEs - Simple Pendulum \ldots}
%%\begin{small}
\typ{In []: from scipy.integrate import odeint}
%%\end{small}
\begin{lstlisting}
In []: pend_sol = odeint(pend_int, 
                         initial,t)
\end{lstlisting}
\end{frame}

\begin{frame}[fragile]
\frametitle{Result}
\begin{center}
\includegraphics[height=2in, interpolate=true]{data/ode}  
\end{center}
\end{frame}

\section{FFTs}

\begin{frame}[fragile]
\frametitle{The FFT}
\begin{itemize}
    \item We have a simple signal $y(t)$
    \item Find the FFT and plot it
\end{itemize}
\begin{lstlisting}
In []: t = linspace(0, 2*pi, 500)
In []: y = sin(4*pi*t)

In []: f = fft(y)
In []: freq = fftfreq(500, t[1] - t[0])

In []: plot(freq[:250], abs(f)[:250])
In []: grid()
\end{lstlisting} 
\end{frame}

\begin{frame}[fragile]
\frametitle{FFTs cont\dots}
\begin{lstlisting}
In []: y1 = ifft(f) # inverse FFT
In []: allclose(y, y1)
Out[]: True
\end{lstlisting} 
\end{frame}

\begin{frame}[fragile]
\frametitle{FFTs cont\dots}
Let us add some noise to the signal
\begin{lstlisting}
In []: yr = y + random(size=500)*0.2
In []: yn = y + normal(size=500)*0.2

In []: plot(t, yr)
In []: figure()
In []: plot(freq[:250],
  ...:      abs(fft(yn))[:250])
\end{lstlisting}
\begin{itemize}
    \item \typ{random}: produces uniform deviates in $[0, 1)$
    \item \typ{normal}: draws random samples from a Gaussian
        distribution
    \item Useful to create a random matrix of any shape
\end{itemize}
\end{frame}

\begin{frame}[fragile]
\frametitle{FFTs cont\dots}
Filter the noisy signal:
\begin{lstlisting}
In []: from scipy import signal
In []: yc = signal.wiener(yn, 5)
In []: clf()
In []: plot(t, yc)
In []: figure()
In []: plot(freq[:250], 
  ...:      abs(fft(yc))[:250])
\end{lstlisting}
Only scratched the surface here \dots
\end{frame}


\begin{frame}
  \frametitle{Things we have learned}
  \begin{itemize}
  \item Least Square Fit
  \item Solving Linear Equations
  \item Defining Functions
  \item Finding Roots
  \item Solving ODEs
  \item Random number generation
  \item FFTs and basic signal processing
  \end{itemize}
\end{frame}

\end{document}

%% Questions for Quiz %%
%% ------------------ %%

\begin{frame}
\frametitle{\incqno }
Given a 4x4 matrix \texttt{A} and a 4-vector \texttt{b}, what command do
you use to solve for the equation \\
\texttt{Ax = b}?
\end{frame}

\begin{frame}
\frametitle{\incqno }
What command will you use if you wish to integrate a system of ODEs?
\end{frame}

\begin{frame}
\frametitle{\incqno }
How do you calculate the roots of the polynomial, $y = 1 + 6x + 8x^2 +
x^3$?
\end{frame}

\begin{frame}
\frametitle{\incqno }
Two arrays \lstinline+a+ and \lstinline+b+ are numerically almost equal, what command
do you use to check if this is true?
\end{frame}

%% \begin{frame}[fragile]
%% \frametitle{\incqno }
%% \begin{lstlisting}
%%   In []: x = arange(0, 1, 0.25)
%%   In []: print x
%% \end{lstlisting}
%% What will be printed?
%% \end{frame}


%% \begin{frame}[fragile]
%% \frametitle{\incqno }
%% \begin{lstlisting}
%% from scipy.integrate import quad
%% def f(x):
%%     res = x*cos(x)
%% quad(f, 0, 1)
%% \end{lstlisting}
%% What changes will you make to the above code to make it work?
%% \end{frame}

%% \begin{frame}
%% \frametitle{\incqno }
%% What two commands will you use to create and evaluate a spline given
%% some data?
%% \end{frame}

%% \begin{frame}[fragile]
%% \frametitle{\incqno }
%% What would be the result?
%% \begin{lstlisting}
%%   In []: x
%%   array([[0, 1, 2],
%%          [3, 4, 5],
%%          [6, 7, 8]])
%%   In []: x[::-1,:]
%% \end{lstlisting}
%% Hint:
%% \begin{lstlisting}
%%   In []: x = arange(9)
%%   In []: x[::-1]
%%   array([8, 7, 6, 5, 4, 3, 2, 1, 0])
%% \end{lstlisting}
%% \end{frame}

%% \begin{frame}[fragile]
%% \frametitle{\incqno }
%% What would be the result?
%% \begin{lstlisting}
%%   In []: y = arange(3)
%%   In []: x = linspace(0,3,3)
%%   In []: x-y
%% \end{lstlisting}
%% \end{frame}

%% \begin{frame}[fragile]
%% \frametitle{\incqno }
%% \begin{lstlisting}
%%   In []: x
%%   array([[ 0, 1, 2, 3],
%%          [ 4, 5, 6, 7],
%%          [ 8, 9, 10, 11],
%%          [12, 13, 14, 15]])
%% \end{lstlisting}
%% How will you get the following \lstinline+x+?
%% \begin{lstlisting}
%%   array([[ 5, 7],
%%          [ 9, 11]])
%% \end{lstlisting}
%% \end{frame}

%% \begin{frame}[fragile]
%% \frametitle{\incqno }
%% What would be the output?
%% \begin{lstlisting}
%%   In []: y = arange(4)
%%   In []: x = array(([1,2,3,2],[1,3,6,0]))
%%   In []: x + y
%% \end{lstlisting}
%% \end{frame}

%% \begin{frame}[fragile]
%% \frametitle{\incqno }
%% \begin{lstlisting}
%%   In []: line = plot(x, sin(x))
%% \end{lstlisting}
%% Use the \lstinline+set_linewidth+ method to set width of \lstinline+line+ to 2.
%% \end{frame}

%% \begin{frame}[fragile]
%% \frametitle{\incqno }
%% What would be the output?
%% \begin{lstlisting}
%%   In []: x = arange(9)
%%   In []: y = arange(9.)
%%   In []: x == y
%% \end{lstlisting}
%% \end{frame}