%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%

% Tutorial slides on Python.

%

% Author: FOSSEE <info at fossee  dot in>

% Copyright (c) 2005-2009, FOSSEE Team

%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%

\documentclass[14pt,compress]{beamer}

\mode<presentation>

{

  \useoutertheme{split}

  \setbeamercovered{transparent}

}

\definecolor{darkgreen}{rgb}{0,0.5,0}

\usepackage{listings}

\lstset{language=Python,

    basicstyle=\ttfamily\bfseries,

    commentstyle=\color{red}\itshape,

  stringstyle=\color{darkgreen},

  showstringspaces=false,

  keywordstyle=\color{blue}\bfseries}

\newcommand{\kwrd}[1]{ \texttt{\textbf{\color{blue}{#1}}}  }

%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%

% Macros

\newcounter{qno}

\setcounter{qno}{0}

\newcommand{\incqno}{\addtocounter{qno}{1}{Question \theqno}}

%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%

% Title page

\title[Basic Python]{Python: Quiz}

\author[FOSSEE Team] {FOSSEE}

\institute[IIT Bombay] {Department of Aerospace Engineering\\IIT Bombay}

\date[] {11, October 2009\\Day 2}

%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%

\begin{document}

\begin{frame}

  \titlepage

\end{frame}

\begin{frame}

  \frametitle{Write your details...}

On the top right hand corner please write down the following:

  \begin{itemize}

    \item  Name:

    \item Affliation:

    \item Occupation:

  \end{itemize}

\end{frame}

\begin{frame}[fragile]

\frametitle{\incqno }

\begin{lstlisting}

  >>> x = array([[1,2,3,4],[3,4,2,5]])

  >>> x.shape

  (2, 4)

\end{lstlisting}

Change the shape of \lstinline+x+ to (4,2)

\end{frame}

\begin{frame}[fragile]

\frametitle{\incqno }

\begin{lstlisting}

  >>> x = array([[1,2,3,4]])

\end{lstlisting}

How to change the third element of \lstinline+x+ to 0?

\end{frame}

\begin{frame}[fragile]

\frametitle{\incqno }

What would be the result?

\begin{lstlisting}

  >>> y = arange(3)

  >>> x = linspace(0,3,3)

  >>> x-y

\end{lstlisting}

\end{frame}

\begin{frame}[fragile]

\frametitle{\incqno }

\begin{lstlisting}

  >>> x = array([0, 1, 2, 3])

  >>> x.shape = 2,2

  >>> x

  array([[0, 1],

         [2, 3]])

  >>> x[::2,::2]

\end{lstlisting}

What is the output?

\end{frame}

\begin{frame}[fragile]

\frametitle{\incqno }

What would be the result?

\begin{lstlisting}

  >>> x

  array([[0, 1, 2],

         [3, 4, 5],

         [6, 7, 8]])

  >>> x[::-1,:]

\end{lstlisting}

Hint:

\begin{lstlisting}

  >>> x = arange(9)

  >>> x[::-1]

  array([8, 7, 6, 5, 4, 3, 2, 1, 0])

\end{lstlisting}

\end{frame}

\begin{frame}[fragile]

\frametitle{\incqno }

\begin{lstlisting}

  >>> x

  array([[ 0, 1, 2, 3],

         [ 4, 5, 6, 7],

         [ 8, 9, 10, 11],

         [12, 13, 14, 15]])

\end{lstlisting}

How will you get the following \lstinline+x+?

\begin{lstlisting}

  array([[ 5, 7],

         [ 9, 11]])

\end{lstlisting}

\end{frame}

\begin{frame}[fragile]

\frametitle{\incqno }

\begin{lstlisting}

  >>> x = array(([1,2,3,4],[2,3,4,5]))

  >>> x[-2][-3] = 4

  >>> x

\end{lstlisting}

What will be printed?

\end{frame}

\begin{frame}[fragile]

\frametitle{\incqno }

What would be the output?

\begin{lstlisting}

  >>> y = arange(4)

  >>> x = array(([1,2,3,2],[1,3,6,0]))

  >>> x + y

\end{lstlisting}

\end{frame}

\begin{frame}[fragile]

\frametitle{\incqno }

\begin{lstlisting}

  >>> line = plot(x, sin(x))

\end{lstlisting}

Use the \lstinline+set_linewidth+ method to set width of \lstinline+line+ to 2.

\end{frame}

\begin{frame}[fragile]

\frametitle{\incqno }

What would be the output?

\begin{lstlisting}

  >>> x = arange(9)

  >>> y = arange(9.)

  >>> x == y

\end{lstlisting}

\end{frame}

\end{document}