accessing-pieces-arrays/questions.rst
changeset 522 d33698326409
parent 521 88a01948450d
child 523 54bdda4aefa5
--- a/accessing-pieces-arrays/questions.rst	Wed Nov 17 23:24:57 2010 +0530
+++ /dev/null	Thu Jan 01 00:00:00 1970 +0000
@@ -1,159 +0,0 @@
-Objective Questions
--------------------
-
-.. A mininum of 8 questions here (along with answers)
-
-1. Given the array, ``A = array([12, 15, 18, 21])``, how do we access
-   the element ``18``?
-
-   Answer: ``A[2]``
-
-#. Given the array, ``A = array([12, 15, 18, 21])``, what element is
-   accessed by ``A[1]``
-
-   Answer: ``15``  
-
-#. Given the array, ``A = array([12, 15, 18, 21])``, what element is
-   accessed by ``A[-3]``?
-
-   Answer: ``15``  
-
-#. Given the array, ``A = array([12, 15, 18, 21])``, how do you change
-   the element ``15`` to ``51``?
-
-   Answer: ``A[1] = 51``
-
-#. Given the array, ``A = array([12, 15, 18, 21])``, what is ``A``
-   after the execution of the statement ``A[3] = 24``?
-
-   Answer: ``array([12, 15, 18, 24])``
-
-#. Given the array, ``A = array([12, 15, 18, 21])``, what is the
-   result of the statement, ``A[4] = 24``?
-
-   Answer: IndexError: index out of bounds
-
-#. Given the array, ``B = array([[12, 15], [18, 21]])``, how do we
-   access the element ``18``? 
-
-   Answer: ``A[0, 0]``
-
-#. Given the array, ``B = array([[12, 15], [18, 21]])``, what is the
-   result of ``B[1]``? 
-
-   Answer:  ``array([18, 21])``
-
-#. Given the array, ``B = array([[12, 15], [18, 21]])``, what is the
-   result of ``B[1, 1]``?
-
-   Answer:  ``21``
-
-#. Given the array, ``B = array([[12, 15], [18, 21]])``, what element
-   is accessed by ``B[-1, -2]``?
-
-   Answer:  ``18``   
-
-#. Given the array, ``B = array([[12, 15], [18, 21]])``, how do you
-   change the element ``15`` to ``51``?
-
-   Answer:  ``B[0, 1] = 51``   
-
-#. Given the array, ``B = array([[12, 15], [18, 21]])``, what is the
-   value of B, after executing, ``B[0] = 0``?
-
-   Answer:  ``array([[0, 0], [18, 21]])``   
-
-#. Given the array, 
-   
-   ::
-   
-     B = array([[10, 11, 12, 13],
-                [20, 21, 22, 23],
-                [30, 31, 32, 33],
-                [40, 41, 42, 43]])
-
-   Obtain the elements, ``[[21, 22], [32, 32]]``
-
-   Answer:  ``B[1:3, 1:3]``   
-
-#. Given the array, 
-   
-   ::
-   
-     B = array([[10, 11, 12, 13],
-                [20, 21, 22, 23],
-                [30, 31, 32, 33],
-                [40, 41, 42, 43]])
-
-   Obtain the elements, ``[[10, 13], [30, 33]]``
-
-   Answer:  ``B[::2, ::3]``
-
-#. What command is used to read an image file?
-
-   a. imshow
-   #. imread
-   #. imopen
-   #. open
-
-   Answer: ``imread``   
-
-#. If ``P`` is ``array([12, 13, 14, 15])`` then ``P.shape`` gives
-   ``(4, 1)``. True or False?
-
-   Answer: False
-     
-Larger Questions
-----------------
-
-.. A minimum of 2 questions here (along with answers)
-
-1. Given the array, 
-   ::
-   
-     B = array([[10, 11, 12, 13],
-                [20, 21, 22, 23],
-                [30, 31, 32, 33],
-                [40, 41, 42, 43]])
-
-   Change the array to 
-   ::
-   
-     B = array([[10, 11, 10, 11],
-                [20, 21, 20, 21],
-                [10, 11, 10, 11],
-                [20, 21, 20, 21]])
-
-   using slicing and striding. 
-
-   Answer::
-
-     B[:2, 2:] = B[:2, :2]
-     B[2:, :2] = B[:2, :2]
-     B[2:, 2:] = B[:2, :2]
-
-#. Find out how to display a grayscale image with proper colors. Hint,
-   use ``?`` on ``imshow``. 
-   
-   Answer: ``cmap=cm.gray``
-                  
-#. From the image, ``tagore-einstein.png``, 
-   a. show only the face of Einstein. 
-   b. show only the face of Tagore. 
-
-   Hint, use ``imread`` to read the image and ``imshow`` to show the
-   image.  Use ``cm.gray`` as ``cmap`` to display the image properly.   
-
-   Answer:: 
-
-     F = imread('tagore-einstein.png')
-     imshow(F[:210, 20:180], cmap=cm.gray)
-
-     F = imread('tagore-einstein.png')
-     imshow(F[30:300, 320:480], cmap=cm.gray)
-
-.. #[Puneeth: This question contains answer to previous
-.. question. Shouldn't be shown at the same time.]
-
-
-