author | Puneeth Chaganti <punchagan@fossee.in> |
Thu, 07 Oct 2010 12:28:12 +0530 | |
changeset 242 | a33e942379d7 |
parent 160 | f394adb5b00e |
permissions | -rw-r--r-- |
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.. 3.2 LO: getting started with =for= (2) [anoop] |
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.. ----------------------------------------------- |
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.. * blocks in python |
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.. + (indentation) |
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.. * blocks in ipython |
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.. + ... prompt |
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.. + hitting enter |
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.. * =for= with a list |
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.. * =range= function |
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============================= |
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Getting started with for loop |
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============================= |
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{{{ show welcome slide }}} |
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Hello and welcome to the tutorial getting started with ``for`` loop. |
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{{{ switch to next slide, outline slide }}} |
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In this tutorial we will see ``for`` loops in python, and also cover |
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the basics of indenting code in python. |
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{{{ switch to next slide, about whitespaces }}} |
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In Python whitespace is significant, and the blocks are visually |
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separated rather than using braces or any other mechanisms for |
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defining blocks. And by this method Python forces the programmers to |
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stick on to one way of writing or beautifying the code rather than |
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debating over where to place the braces. This way it produces uniform |
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code than obscure or unreadable code. |
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A block may be defined by a suitable indentation level which can be |
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either be a tab or few spaces. And the best practice is to indent the |
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code using four spaces. |
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Now let us move straight into ``for`` loop. |
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{{{ switch to next slide, problem statement of exercise 1 }}} |
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Write a for loop which iterates through a list of numbers and find the |
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square root of each number. Also make a new list with the square roots |
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and print it at the end. |
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:: |
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numbers are 1369, 7225, 3364, 7056, 5625, 729, 7056, 576, 2916 |
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For the problem, first we need to create a ``list`` of numbers and |
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then iterate over the list and find the square root of each element in |
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it. And let us create a script, rather than typing it out in the |
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interpreter itself. Create a script called list_roots.py and type the |
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following. |
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53 |
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{{{ open the text editor and paste the following code there }}} |
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:: |
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numbers = [1369, 7225, 3364, 7056, 5625, 729, 7056, 576, 2916] |
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square_roots = [] |
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for each in numbers: |
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sq_root = sqrt(each) |
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print "Square root of", each, "is", sq_root |
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square_roots.append(sq_root) |
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print square_roots |
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{{{ save the script }}} |
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Now save the script, and run it from your IPython interpreter. I |
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assume that you have started your IPython interpreter using ``-pylab`` |
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option. |
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71 |
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Run the script as, |
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73 |
:: |
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74 |
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%run -i list_roots.py |
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76 |
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{{{ run the script }}} |
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78 |
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79 |
So that was easy! We didn't have to find the length of the string nor |
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80 |
address of each element of the list one by one. All what we did was |
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iterate over the list element by element and then use the element for |
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calculation. Note that here we used three variables. One the variable |
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``numbers``, which is a list, another one ``each``, which is the |
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84 |
element of list under consideration in each cycle of the ``for`` loop, |
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85 |
and then a variable ``sq_root`` for storing the square root in each |
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cycle of the ``for`` loop. The variable names can be chosen by you. |
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87 |
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88 |
{{{ show the script which was created }}} |
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89 |
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90 |
Note that three lines after ``for`` statement, are indented using four |
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91 |
spaces. |
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92 |
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93 |
{{{ highlight the threee lines after for statement }}} |
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94 |
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95 |
It means that those three lines are part of the for loop. And it is |
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96 |
called a block of statements. And the seventh line or the immediate |
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97 |
line after the third line in the ``for`` loop is not indented, |
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98 |
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99 |
{{{ highlight the seventh line - the line just after for loop }}} |
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100 |
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101 |
it means that it is not part of the ``for`` loop and the lines after |
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102 |
that doesn't fall in the scope of the ``for`` loop. Thus each block is |
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103 |
separated by the indentation level. Thus marking the importance of |
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104 |
white-spaces in Python. |
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105 |
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106 |
{{{ switch to the slide which shows the problem statement of the first |
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107 |
problem to be tried out }}} |
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108 |
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109 |
Now a question for you to try, from the given numbers make a list of |
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110 |
perfect squares and a list of those which are not. The numbers are, |
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111 |
:: |
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112 |
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113 |
7225, 3268, 3364, 2966, 7056, 5625, 729, 5547, 7056, 576, 2916 |
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114 |
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115 |
{{{ switch to next slide, problem statement of second problem in |
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116 |
solved exercie}}} |
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117 |
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118 |
Now let us try a simple one, to print the square root of numbers in |
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119 |
the list. And this time let us do it right in the IPython |
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120 |
interpreter. |
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121 |
|
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122 |
{{{ switch focus to the IPython interpreter }}} |
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123 |
|
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124 |
So let us start with making a list. Type the following |
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125 |
:: |
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126 |
|
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127 |
numbers = [1369, 7225, 3364, 7056, 5625, 729, 7056, 576, 2916] |
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128 |
for each in numbers: |
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129 |
|
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130 |
and now you will notice that, as soon as you press the return key |
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131 |
after for statement, the prompt changes to four dots and the cursor is |
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132 |
not right after the four dots but there are four spaces from the |
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133 |
dots. The four dots tell you that you are inside a block. Now type the |
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134 |
rest of the ``for`` loop, |
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135 |
:: |
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136 |
|
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137 |
sq_root = sqrt(each) |
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138 |
print "Square root of", each, "is", sq_root |
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139 |
|
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140 |
Now we have finished the statements in the block, and still the |
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141 |
interpreter is showing four dots, which means you are still inside the |
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142 |
block. To exit from the block press return key or the enter key twice |
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143 |
without entering anything else. It printed the square root of each |
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144 |
number in the list, and that is executed in a ``for`` loop. |
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145 |
|
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146 |
Now, let us generate the multiplication table of 10 from one to |
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147 |
ten. But this time let us try it in the vanilla version of Python |
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148 |
interpreter. |
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149 |
|
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150 |
Start the vanilla version of Python interpreter by issuing the command |
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151 |
``python`` in your terminal. |
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152 |
|
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153 |
{{{ open the python interpreter in the terminal using the command |
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154 |
python to start the vanilla Python interpreter }}} |
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155 |
|
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156 |
Start with, |
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157 |
:: |
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158 |
|
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159 |
for i in range(1,11): |
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160 |
|
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161 |
and press enter once, and we will see that this time it shows four |
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162 |
dots, but the cursor is close to the dots, so we have to intend the |
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163 |
block. So enter four spaces there and then type the following |
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164 |
:: |
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165 |
|
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166 |
|
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167 |
print "10 *",i,"=",i*10 |
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168 |
|
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169 |
Now when we hit enter, we still see the four dots, to get out of the |
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170 |
block type enter once. |
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171 |
|
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172 |
Okay! so the main thing here we learned is how to use Python |
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173 |
interpreter and IPython interpreter to specify blocks. But while we |
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174 |
were generating the multiplication table we used something new, |
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175 |
``range()`` function. ``range()`` is an inbuilt function in Python |
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176 |
which can be used to generate a ``list`` of integers from a starting |
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177 |
range to an ending range. Note that the ending number that you specify |
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178 |
will not be included in the ``list``. |
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179 |
|
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180 |
Now, let us print all the odd numbers from 1 to 50. Let us do it in |
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181 |
our IPython interpreter for ease of use. |
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182 |
|
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183 |
{{{ switch focus to ipython interpreter }}} |
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184 |
|
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185 |
{{{ switch to next slide, problem statement of the next problem in |
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186 |
solved exercises }}} |
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187 |
|
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188 |
Print the list of odd numbers from 1 to 50. It will be better if |
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189 |
you can try it out yourself. |
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190 |
|
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191 |
It is a very trivial problem and can be solved as, |
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192 |
:: |
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193 |
|
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194 |
print range(1,51,2) |
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195 |
|
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196 |
This time we passed three parameters to ``range()`` function unlike |
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197 |
the previous case where we passed only two parameters. The first two |
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198 |
parameters are the same in both the cases. The first parameter is the |
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199 |
starting number of the sequence and the second parameter is the end of |
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200 |
the range. Note that the sequence doesn't include the ending |
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201 |
number. The third parameter is for stepping through the sequence. Here |
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202 |
we gave two which means we are skipping every alternate element. |
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203 |
|
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204 |
{{{ switch to next slide, recap slide }}} |
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205 |
|
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anoop
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206 |
Thus we come to the end of this tutorial. We learned about blocks in |
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207 |
Python, indentation, blocks in IPython, for loop, iterating over a |
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208 |
list and then the ``range()`` function. |
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209 |
|
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210 |
{{{ switch to next slide, thank you slide }}} |
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211 |
|
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212 |
Thank you! |
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213 |
|
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214 |
.. Author: Anoop Jacob Thomas <anoop@fossee.in> |
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215 |
Reviewer 1: |
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216 |
Reviewer 2: |
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217 |
External reviewer: |