.. 3.2 LO: getting started with =for= (2) [anoop] 

.. -----------------------------------------------

.. * blocks in python 

..   + (indentation) 

.. * blocks in ipython 

..   + ... prompt 

..   + hitting enter 

.. * =for= with a list 

.. * =range= function 

=============================

Getting started with for loop

=============================

{{{ show welcome slide }}}

Hello and welcome to the tutorial getting started with ``for`` loop. 

{{{ switch to next slide, outline slide }}}

In this tutorial we will see ``for`` loops in python, and also cover

the basics of indenting code in python.

.. #[Nishanth]: Instead of saying basics of indenting code,

                say How to define code blocks in Python

{{{ switch to next slide, about whitespaces }}}

In Python whitespace is significant, and the blocks are visually

separated rather than using braces or any other mechanisms for

defining blocks. And by this method Python forces the programmers to

stick on to one way of writing or beautifying the code rather than

debating over where to place the braces. This way it produces uniform

code than obscure or unreadable code.

.. #[nishanth]: Simply tell how blocks are defined in python.

                The details like braces are not used and its

                advantages like neat code can be told after completely

                explaining the indentation

A block may be defined by a suitable indentation level which can be

either be a tab or few spaces. And the best practice is to indent the

code using four spaces.

.. #[Nishanth]: Even this detail may be skipped. Simply say use 4 spaces

                for indentation. Do that while typing so that they can

                actually see what is being typed.

Now let us move straight into ``for`` loop.

{{{ switch to next slide, problem statement of exercise 1 }}}

Write a for loop which iterates through a list of numbers and find the

square root of each number. Also make a new list with the square roots

and print it at the end.

.. #[nishanth]: making new list with square roots induces extra complication

                like appending which has no use case here

::

    numbers are 1369, 7225, 3364, 7056, 5625, 729, 7056, 576, 2916

.. #[Nishanth]: The problem focuses more on square root and creation

                of list. The problem must be simple and focusing on 

                nothing more but the indentation and for loop.

                May be change the problem to print squares than to

                print square roots.

For the problem, first we need to create a ``list`` of numbers and

then iterate over the list and find the square root of each element in

it. And let us create a script, rather than typing it out in the

interpreter itself. Create a script called list_roots.py and type the

following.

{{{ open the text editor and paste the following code there }}}

::

    numbers = [1369, 7225, 3364, 7056, 5625, 729, 7056, 576, 2916]

    square_roots = []

    for each in numbers:

        sq_root = sqrt(each)

        print "Square root of", each, "is", sq_root

        square_roots.append(sq_root)

    print 

    print square_roots

..  numbers = [1, 12, 3, 4, 21, 17]

    for each in numbers:

        print each, each * each

.. #[nishanth]: I don't see a use case to append the sq_root to

                square_roots. It is only complicating stuff.

                Simply iterate and print.

{{{ save the script }}}

Now save the script, and run it from your IPython interpreter. I

assume that you have started your IPython interpreter using ``-pylab``

option.

Run the script as,

::

    %run -i list_roots.py

.. #[Nishanth]: you don't have to use the -i option here

{{{ run the script }}}

So that was easy! We didn't have to find the length of the string nor

address of each element of the list one by one. All what we did was

iterate over the list element by element and then use the element for

calculation. Note that here we used three variables. One the variable

``numbers``, which is a list, another one ``each``, which is the

element of list under consideration in each cycle of the ``for`` loop,

and then a variable ``sq_root`` for storing the square root in each

cycle of the ``for`` loop. The variable names can be chosen by you.

.. #[Nishanth]: The details like we didn't have to find the length

                are relevant for people who have programmed in C or

                other languages earlier. But for a newbie it is more

                of confusing extra info. That part may be skipped.

                Simply go ahead and focus on the syntax of for loop.

                And how the variable name is used inside the for loop.

                If you modify the question to only print, the extra 

                variable sq_root can also be avoided. let it be more

                about "each", "numbers" and "for". no other new names.

{{{ show the script which was created }}}

Note that three lines after ``for`` statement, are indented using four

spaces.

{{{ highlight the three lines after for statement }}}

It means that those three lines are part of the for loop. And it is

called a block of statements. And the seventh line or the immediate

line after the third line in the ``for`` loop is not indented, 

{{{ highlight the seventh line - the line just after for loop }}}

it means that it is not part of the ``for`` loop and the lines after

that doesn't fall in the scope of the ``for`` loop. Thus each block is

separated by the indentation level. Thus marking the importance of

white-spaces in Python.

{{{ switch to the slide which shows the problem statement of the first

problem to be tried out }}}

Now a question for you to try, from the given numbers make a list of

perfect squares and a list of those which are not. The numbers are,

::

    7225, 3268, 3364, 2966, 7056, 5625, 729, 5547, 7056, 576, 2916

{{{ switch to next slide, problem statement of second problem in

solved exercie}}}

Now let us try a simple one, to print the square root of numbers in

the list. And this time let us do it right in the IPython

interpreter. 

{{{ switch focus to the IPython interpreter }}}

So let us start with making a list. Type the following

::

    numbers = [1369, 7225, 3364, 7056, 5625, 729, 7056, 576, 2916]

    for each in numbers:

and now you will notice that, as soon as you press the return key

after for statement, the prompt changes to four dots and the cursor is

not right after the four dots but there are four spaces from the

dots. The four dots tell you that you are inside a block. Now type the

rest of the ``for`` loop,

.. #[Nishanth]: Tell that IPython does auto indentation.

::

        sq_root = sqrt(each)

        print "Square root of", each, "is", sq_root

Now we have finished the statements in the block, and still the

interpreter is showing four dots, which means you are still inside the

block. To exit from the block press return key or the enter key twice

without entering anything else. It printed the square root of each

number in the list, and that is executed in a ``for`` loop.

Now, let us generate the multiplication table of 10 from one to

ten. But this time let us try it in the vanilla version of Python

interpreter.

Start the vanilla version of Python interpreter by issuing the command

``python`` in your terminal.

{{{ open the python interpreter in the terminal using the command

python to start the vanilla Python interpreter }}}

Start with,

::

    for i in range(1,11):

and press enter once, and we will see that this time it shows four

dots, but the cursor is close to the dots, so we have to indent the

block. So enter four spaces there and then type the following

::

        print "10 x",i,"=",i*10

Now when we hit enter, we still see the four dots, to get out of the

block, hit enter once again

.. #[Nishanth]: Here also the overhead on print can be reduced.

                Think of a simple print statement. This statement

                will be confusing for a newbie.

                We can focus more on indentation in python.

.. #[nishanth]: Not sure if you must use range here. You can 

                define a list of numbers and iterate on it.

                Then say this list can also be generated using

                the range function and hence introduce range.

Okay! so the main thing here we learned is how to use Python

interpreter and IPython interpreter to specify blocks. But while we

were generating the multiplication table we used something new,

``range()`` function. ``range()`` is an inbuilt function in Python

which can be used to generate a ``list`` of integers from a starting

number to an ending number. Note that the ending number that you specify

will not be included in the ``list``.

.. #[Nishanth]: Show some examples of range without the step argument

                May be give an exercise with negative numbers as arguments

Now, let us print all the odd numbers from 1 to 50. Let us do it in

our IPython interpreter for ease of use.

{{{ switch focus to ipython interpreter }}}

{{{ switch to next slide, problem statement of the next problem in

solved exercises }}}

Print the list of odd numbers from 1 to 50. It will be better if

you can try it out yourself.

It is a very trivial problem and can be solved as,

::

    print range(1,51,2)

This time we passed three parameters to ``range()`` function unlike

the previous case where we passed only two parameters. The first two

parameters are the same in both the cases. The first parameter is the

starting number of the sequence and the second parameter is the end of

the range. Note that the sequence doesn't include the ending

number. The third parameter is for stepping through the sequence. Here

we gave two which means we are skipping every alternate element.

{{{ switch to next slide, recap slide }}}

Thus we come to the end of this tutorial. We learned about blocks in

Python, indentation, blocks in IPython, for loop, iterating over a

list and then the ``range()`` function.

{{{ switch to next slide, thank you slide }}}

Thank you!

..  Author: Anoop Jacob Thomas <anoop@fossee.in>

    Reviewer 1: Nishanth

    Reviewer 2:

    External reviewer: