parts/django/tests/modeltests/unmanaged_models/models.py
changeset 69 c6bca38c1cbf
--- /dev/null	Thu Jan 01 00:00:00 1970 +0000
+++ b/parts/django/tests/modeltests/unmanaged_models/models.py	Sat Jan 08 11:20:57 2011 +0530
@@ -0,0 +1,125 @@
+"""
+Models can have a ``managed`` attribute, which specifies whether the SQL code
+is generated for the table on various manage.py operations.
+"""
+
+from django.db import models
+
+#  All of these models are creatd in the database by Django.
+
+class A01(models.Model):
+    f_a = models.CharField(max_length=10, db_index=True)
+    f_b = models.IntegerField()
+
+    class Meta:
+        db_table = 'A01'
+
+    def __unicode__(self):
+        return self.f_a
+
+class B01(models.Model):
+    fk_a = models.ForeignKey(A01)
+    f_a = models.CharField(max_length=10, db_index=True)
+    f_b = models.IntegerField()
+
+    class Meta:
+        db_table = 'B01'
+        # 'managed' is True by default. This tests we can set it explicitly.
+        managed = True
+
+    def __unicode__(self):
+        return self.f_a
+
+class C01(models.Model):
+    mm_a = models.ManyToManyField(A01, db_table='D01')
+    f_a = models.CharField(max_length=10, db_index=True)
+    f_b = models.IntegerField()
+
+    class Meta:
+        db_table = 'C01'
+
+    def __unicode__(self):
+        return self.f_a
+
+# All of these models use the same tables as the previous set (they are shadows
+# of possibly a subset of the columns). There should be no creation errors,
+# since we have told Django they aren't managed by Django.
+
+class A02(models.Model):
+    f_a = models.CharField(max_length=10, db_index=True)
+
+    class Meta:
+        db_table = 'A01'
+        managed = False
+
+    def __unicode__(self):
+        return self.f_a
+
+class B02(models.Model):
+    class Meta:
+        db_table = 'B01'
+        managed = False
+
+    fk_a = models.ForeignKey(A02)
+    f_a = models.CharField(max_length=10, db_index=True)
+    f_b = models.IntegerField()
+
+    def __unicode__(self):
+        return self.f_a
+
+# To re-use the many-to-many intermediate table, we need to manually set up
+# things up.
+class C02(models.Model):
+    mm_a = models.ManyToManyField(A02, through="Intermediate")
+    f_a = models.CharField(max_length=10, db_index=True)
+    f_b = models.IntegerField()
+
+    class Meta:
+        db_table = 'C01'
+        managed = False
+
+    def __unicode__(self):
+        return self.f_a
+
+class Intermediate(models.Model):
+    a02 = models.ForeignKey(A02, db_column="a01_id")
+    c02 = models.ForeignKey(C02, db_column="c01_id")
+
+    class Meta:
+        db_table = 'D01'
+        managed = False
+
+#
+# These next models test the creation (or not) of many to many join tables
+# between managed and unmanaged models. A join table between two unmanaged
+# models shouldn't be automatically created (see #10647).
+#
+
+# Firstly, we need some models that will create the tables, purely so that the
+# tables are created. This is a test setup, not a requirement for unmanaged
+# models.
+class Proxy1(models.Model):
+    class Meta:
+        db_table = "unmanaged_models_proxy1"
+
+class Proxy2(models.Model):
+    class Meta:
+        db_table = "unmanaged_models_proxy2"
+
+class Unmanaged1(models.Model):
+    class Meta:
+        managed = False
+        db_table = "unmanaged_models_proxy1"
+
+# Unmanged with an m2m to unmanaged: the intermediary table won't be created.
+class Unmanaged2(models.Model):
+    mm = models.ManyToManyField(Unmanaged1)
+
+    class Meta:
+        managed = False
+        db_table = "unmanaged_models_proxy2"
+
+# Here's an unmanaged model with an m2m to a managed one; the intermediary
+# table *will* be created (unless given a custom `through` as for C02 above).
+class Managed1(models.Model):
+    mm = models.ManyToManyField(Unmanaged1)