Allow for multiple list objects
At the moment there's not really a practical use for it, since there
is no way to make soc.views.models.base.View.list() show more than
one list, but it shouldn't be too hard to allow for that.
Patch by: Sverre Rabbelier
#!/usr/bin/python2.5
#
# Copyright 2008 the Melange authors.
#
# Licensed under the Apache License, Version 2.0 (the "License");
# you may not use this file except in compliance with the License.
# You may obtain a copy of the License at
#
# http://www.apache.org/licenses/LICENSE-2.0
#
# Unless required by applicable law or agreed to in writing, software
# distributed under the License is distributed on an "AS IS" BASIS,
# WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
# See the License for the specific language governing permissions and
# limitations under the License.
"""Helpers used to render lists.
"""
__authors__ = [
'"Chen Lunpeng" <forever.clp@gmail.com>',
'"Pawel Solyga" <pawel.solyga@gmail.com>',
]
from soc.views import helper
import soc.views.helper.forms
DEF_PAGINATION = 10
MAX_PAGINATION = 100
DEF_PAGINATION_CHOICES = (
('10', '10 items per page'),
('25', '25 items per page'),
('50', '50 items per page'),
('100', '100 items per page'),
)
def getPreferredListPagination(user=None):
"""Returns User's preferred list pagination limit.
Args:
user: User entity containing the list pagination preference;
default is None, to use the current logged-in User
"""
# TODO: eventually this limit should be a User profile preference
# (stored in the site-wide User Model) preference
return DEF_PAGINATION
def cleanListParameters(offset=None, limit=None):
"""Converts and validates offset and limit values of the list.
Args:
offset: offset in list which defines first item to return
limit: max amount of items per page
Returns:
updated offset and limit values
"""
# update offset value
try:
offset = int(offset)
except:
# also catches offset=None case where offset not supplied
offset = 0
# update limit value
try:
limit = int(limit)
except:
# also catches limit=None case where limit not supplied
limit = getPreferredListPagination()
return max(0, offset), max(1, min(limit, MAX_PAGINATION))
def getList(request, list_data, list_templates, description, offset=0, limit=0):
"""Returns a dict with fields used for rendering lists.
Args:
request: the Django HTTP request object
list_data: array of data to be displayed in the list
offset: offset in list which defines first item to return
limit: max amount of items per page
list_templates: templates that are used when rendering list
Returns:
A a dictionary with the following values set:
{
'data': list data to be displayed
'main': url to list main template
'pagination': url to list pagination template
'row': url to list row template
'heading': url to list heading template
'limit': max amount of items per page,
'newest': url to first page of the list
'prev': url to previous page
'next': url to next page
'first': offset of the first item in the list
'last': offest of the lst item in the list
}
"""
if not list_data:
list_data = []
more = bool(list_data[limit:])
if more:
del list_data[limit:]
newest = ''
next = ''
prev = ''
if more:
next = request.path + '?offset=%d&limit=%d' % (offset+limit, limit)
if offset > 0:
prev = request.path + '?offset=%d&limit=%d' % (max(0, offset-limit), limit)
if offset > limit:
newest = request.path + '?limit=%d' % limit
content = {
'data': list_data,
'description': description,
'main': list_templates['list_main'],
'pagination': list_templates['list_pagination'],
'row': list_templates['list_row'],
'heading': list_templates['list_heading'],
'limit': limit,
'newest': newest,
'prev': prev,
'next': next,
'first': offset+1,
'last': len(list_data) > 1 and offset+len(list_data) or None
}
return content
def makePaginationForm(
request, limit, arg_name='limit', choices=DEF_PAGINATION_CHOICES,
field_name_fmt=helper.forms.DEF_SELECT_QUERY_ARG_FIELD_NAME_FMT):
"""Returns a customized pagination limit selection form.
Args:
request: the standard Django HTTP request object
limit: the initial value of the selection control
arg_name: see helper.forms.makeSelectQueryArgForm(); default is 'limit'
choices: see helper.forms.makeSelectQueryArgForm(); default is
DEF_PAGINATION_CHOICES
field_name_fmt: see helper.forms.makeSelectQueryArgForm()
"""
choices = makeNewPaginationChoices(limit=limit, choices=choices)
return helper.forms.makeSelectQueryArgForm(
request, arg_name, limit, choices)
def makeNewPaginationChoices(limit=DEF_PAGINATION,
choices=DEF_PAGINATION_CHOICES):
"""Updates the pagination limit selection form.
Args:
limit: the initial value of the selection control;
default is DEF_PAGINATION
choices: see helper.forms.makeSelectQueryArgForm();
default is DEF_PAGINATION_CHOICES
Returns:
a new pagination choices list if limit is not in
DEF_PAGINATION_CHOICES, or DEF_PAGINATION_CHOICES otherwise
"""
# determine where to insert the new limit into choices
new_choices = []
for index, (pagination, label) in enumerate(choices):
items = int(pagination)
if limit == items:
# limit is already present, so just return existing choices
return choices
if limit < items:
# limit needs to be inserted before the current pagination,
# so assemble a new choice tuple and append it
choice = (str(limit), '%s items per page' % limit)
new_choices.append(choice)
# append the remainder of the original list and exit early
# (avoiding unnecessary remaining type conversions, etc.)
new_choices.extend(choices[index:])
return new_choices
# append the existing choice
new_choices.append((pagination, label))
# new choice must go last, past all other existing choices
choice = (str(limit), '%s items per page' % limit)
new_choices.append(choice)
return new_choices