app/soc/views/helper/lists.py
author Sverre Rabbelier <srabbelier@gmail.com>
Fri, 21 Nov 2008 23:45:37 +0000
changeset 539 e30462354e26
parent 499 d22e4fe8e64b
child 553 c0cc20b4afc9
permissions -rw-r--r--
Allow for multiple list objects At the moment there's not really a practical use for it, since there is no way to make soc.views.models.base.View.list() show more than one list, but it shouldn't be too hard to allow for that. Patch by: Sverre Rabbelier

#!/usr/bin/python2.5
#
# Copyright 2008 the Melange authors.
#
# Licensed under the Apache License, Version 2.0 (the "License");
# you may not use this file except in compliance with the License.
# You may obtain a copy of the License at
#
#   http://www.apache.org/licenses/LICENSE-2.0
#
# Unless required by applicable law or agreed to in writing, software
# distributed under the License is distributed on an "AS IS" BASIS,
# WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
# See the License for the specific language governing permissions and
# limitations under the License.

"""Helpers used to render lists.
"""

__authors__ = [
  '"Chen Lunpeng" <forever.clp@gmail.com>',
  '"Pawel Solyga" <pawel.solyga@gmail.com>',
  ]


from soc.views import helper

import soc.views.helper.forms


DEF_PAGINATION = 10
MAX_PAGINATION = 100

DEF_PAGINATION_CHOICES = (
  ('10', '10 items per page'),
  ('25', '25 items per page'),
  ('50', '50 items per page'),
  ('100', '100 items per page'),
)


def getPreferredListPagination(user=None):
  """Returns User's preferred list pagination limit.
  
  Args:
    user: User entity containing the list pagination preference;
      default is None, to use the current logged-in User
  """
  # TODO: eventually this limit should be a User profile preference
  #   (stored in the site-wide User Model) preference 
  return DEF_PAGINATION


def cleanListParameters(offset=None, limit=None):
  """Converts and validates offset and limit values of the list.

  Args:
    offset: offset in list which defines first item to return
    limit: max amount of items per page

  Returns:
    updated offset and limit values
  """
  # update offset value
  try:
    offset = int(offset)
  except:
    # also catches offset=None case where offset not supplied
    offset = 0

  # update limit value
  try:
    limit = int(limit)
  except:
    # also catches limit=None case where limit not supplied
    limit = getPreferredListPagination()

  return max(0, offset), max(1, min(limit, MAX_PAGINATION))


def getList(request, list_data, list_templates, description, offset=0, limit=0):
  """Returns a dict with fields used for rendering lists.

  Args:
    request: the Django HTTP request object
    list_data: array of data to be displayed in the list
    offset: offset in list which defines first item to return
    limit: max amount of items per page
    list_templates: templates that are used when rendering list

  Returns:
    A a dictionary with the following values set:

    {
      'data': list data to be displayed
      'main': url to list main template
      'pagination': url to list pagination template
      'row': url to list row template
      'heading': url to list heading template
      'limit': max amount of items per page,
      'newest': url to first page of the list 
      'prev': url to previous page 
      'next': url to next page
      'first': offset of the first item in the list
      'last': offest of the lst item in the list
    }
  """

  if not list_data:
    list_data = []

  more = bool(list_data[limit:])
  if more:
    del list_data[limit:]

  newest = ''
  next = ''
  prev = ''

  if more:
    next = request.path + '?offset=%d&limit=%d' % (offset+limit, limit)

  if offset > 0:
    prev = request.path + '?offset=%d&limit=%d' % (max(0, offset-limit), limit)

  if offset > limit:
    newest = request.path + '?limit=%d' % limit

  content = {
      'data': list_data,
      'description': description,
     'main': list_templates['list_main'],
     'pagination': list_templates['list_pagination'],
     'row': list_templates['list_row'],
     'heading': list_templates['list_heading'],
     'limit': limit,
     'newest': newest, 
     'prev': prev, 
     'next': next,
     'first': offset+1,
     'last': len(list_data) > 1 and offset+len(list_data) or None
     }

  return content


def makePaginationForm(
  request, limit, arg_name='limit', choices=DEF_PAGINATION_CHOICES,
  field_name_fmt=helper.forms.DEF_SELECT_QUERY_ARG_FIELD_NAME_FMT):
  """Returns a customized pagination limit selection form.
  
  Args:
    request: the standard Django HTTP request object
    limit: the initial value of the selection control
    arg_name: see helper.forms.makeSelectQueryArgForm(); default is 'limit'
    choices: see helper.forms.makeSelectQueryArgForm(); default is
      DEF_PAGINATION_CHOICES
    field_name_fmt: see helper.forms.makeSelectQueryArgForm()
  """
  choices = makeNewPaginationChoices(limit=limit, choices=choices)
  
  return helper.forms.makeSelectQueryArgForm(
      request, arg_name, limit, choices)


def makeNewPaginationChoices(limit=DEF_PAGINATION,
                             choices=DEF_PAGINATION_CHOICES):
  """Updates the pagination limit selection form.

  Args:
    limit: the initial value of the selection control;
      default is DEF_PAGINATION
    choices: see helper.forms.makeSelectQueryArgForm();
      default is DEF_PAGINATION_CHOICES

  Returns:
    a new pagination choices list if limit is not in
    DEF_PAGINATION_CHOICES, or DEF_PAGINATION_CHOICES otherwise
  """
  # determine where to insert the new limit into choices
  new_choices = []
  
  for index, (pagination, label) in enumerate(choices):
    items = int(pagination)

    if limit == items:
      # limit is already present, so just return existing choices
      return choices

    if limit < items:
      # limit needs to be inserted before the current pagination,
      # so assemble a new choice tuple and append it 
      choice = (str(limit), '%s items per page' % limit)
      new_choices.append(choice)
      
      # append the remainder of the original list and exit early
      # (avoiding unnecessary remaining type conversions, etc.)
      new_choices.extend(choices[index:])
      return new_choices

    # append the existing choice
    new_choices.append((pagination, label))

  # new choice must go last, past all other existing choices
  choice = (str(limit), '%s items per page' % limit)
  new_choices.append(choice)
      
  return new_choices