No override needed in notifications.py
The only downside is that the ?s=0 parameter will still be appended
but is not handled in list(). The right solution would be to update
list() so that it does say "Message Sent" or such, to give the user
an indication that their message was sent succesfully.
Patch by: Sverre Rabbelier
from django.core.management.base import NoArgsCommand
def module_to_dict(module, omittable=lambda k: k.startswith('_')):
"Converts a module namespace to a Python dictionary. Used by get_settings_diff."
return dict([(k, repr(v)) for k, v in module.__dict__.items() if not omittable(k)])
class Command(NoArgsCommand):
help = """Displays differences between the current settings.py and Django's
default settings. Settings that don't appear in the defaults are
followed by "###"."""
requires_model_validation = False
def handle_noargs(self, **options):
# Inspired by Postfix's "postconf -n".
from django.conf import settings, global_settings
# Because settings are imported lazily, we need to explicitly load them.
settings._import_settings()
user_settings = module_to_dict(settings._target)
default_settings = module_to_dict(global_settings)
output = []
keys = user_settings.keys()
keys.sort()
for key in keys:
if key not in default_settings:
output.append("%s = %s ###" % (key, user_settings[key]))
elif user_settings[key] != default_settings[key]:
output.append("%s = %s" % (key, user_settings[key]))
print '\n'.join(output)