Make it possible to invite another Host as Host
We do this by asking Django to resolve the current url for us, then
reshufle that url and ask Django (again) to resolve that new url.
From that resolved url we know the appropriate view, and as such we
know which rights dictioanry to pass to access.checkAccess.
Patch by: Sverre Rabbelier
#!/usr/bin/env python
#
# Copyright 2007 Google Inc.
#
# Licensed under the Apache License, Version 2.0 (the "License");
# you may not use this file except in compliance with the License.
# You may obtain a copy of the License at
#
# http://www.apache.org/licenses/LICENSE-2.0
#
# Unless required by applicable law or agreed to in writing, software
# distributed under the License is distributed on an "AS IS" BASIS,
# WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
# See the License for the specific language governing permissions and
# limitations under the License.
#
import wsgiref.handlers
from google.appengine.ext import webapp
class MainHandler(webapp.RequestHandler):
def get(self):
self.response.out.write('Hello world!')
def main():
application = webapp.WSGIApplication([('/', MainHandler)],
debug=True)
wsgiref.handlers.CGIHandler().run(application)
if __name__ == '__main__':
main()