app/soc/views/site/sponsor/list.py
author Pawel Solyga <Pawel.Solyga@gmail.com>
Thu, 16 Oct 2008 15:22:41 +0000
changeset 358 843d83b87282
parent 344 d135c8c09967
child 360 5ad9cabb5892
permissions -rw-r--r--
Add page=None parameter to all views. Information from page argument (which is soc.logic.site.page.Page object) is going to be used later in views code and for some context values. Fix some indentions in __doc__ strings. Add proper __doc__ string for all() function in sponsor/list.py module. Patch by: Pawel Solyga Review by: to-be-reviewed

#!/usr/bin/python2.5
#
# Copyright 2008 the Melange authors.
#
# Licensed under the Apache License, Version 2.0 (the "License");
# you may not use this file except in compliance with the License.
# You may obtain a copy of the License at
#
#   http://www.apache.org/licenses/LICENSE-2.0
#
# Unless required by applicable law or agreed to in writing, software
# distributed under the License is distributed on an "AS IS" BASIS,
# WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
# See the License for the specific language governing permissions and
# limitations under the License.

"""Developer views for listing Sponsors profiles.
"""

__authors__ = [
  '"Pawel Solyga" <pawel.solyga@gmail.com>',
  ]


from soc.logic import models
from soc.logic.models import sponsor
from soc.views import helper
from soc.views import simple
from soc.views.helper import access

import soc.logic
import soc.models.sponsor as sponsor_model
import soc.views.helper.lists
import soc.views.helper.responses
import soc.views.out_of_band


DEF_SITE_SPONSOR_LIST_ALL_TMPL = 'soc/group/list/all.html'

def all(request, page=None, template=DEF_SITE_SPONSOR_LIST_ALL_TMPL):
  """Show a list of all Sponsors (limit rows per page).
  
  Args:
    request: the standard Django HTTP request object
    page: a soc.logic.site.page.Page object which is abstraction that combines 
      a Django view with sidebar menu info
    template: the "sibling" template (or a search list of such templates)
      from which to construct an alternate template name (or names)

  Returns:
    A subclass of django.http.HttpResponse which either contains the form to
    be filled out, or a redirect to the correct view in the interface.
  """

  try:
    access.checkIsDeveloper(request)
  except  soc.views.out_of_band.AccessViolationResponse, alt_response:
    return alt_response.response()

  # create default template context for use with any templates
  context = helper.responses.getUniversalContext(request)

  offset, limit = helper.lists.cleanListParameters(
      offset=request.GET.get('offset'), limit=request.GET.get('limit'))
  
  # Fetch one more to see if there should be a 'next' link
  sponsors = models.sponsor.logic.getForLimitAndOffset(limit=limit + 1,
                                                       offset=offset)

  context['pagination_form'] = helper.lists.makePaginationForm(request, limit)
  
  list_templates = {'list_main': 'soc/list/list_main.html',
                    'list_pagination': 'soc/list/list_pagination.html',
                    'list_row': 'soc/group/list/group_row.html',
                    'list_heading': 'soc/group/list/group_heading.html'}
                      
  context = helper.lists.setList(request, context, sponsors, 
                                 offset=offset, limit=limit, 
                                 list_templates=list_templates)
                                 
  context.update({'group_type': 'Sponsor',
                  'group_type_plural': sponsor_model.Sponsor.GROUP_TYPE_PLURAL,
                  'group_type_short': sponsor_model.Sponsor.GROUP_TYPE_SHORT})

  return helper.responses.respond(request, template, context)