Added a filter method to dicts
The best way to explain this is probably with an example:
>>> split({'foo':'bar', 'bar':['one', 'two'], 'baz': ['three', 'four']})
[{'bar': 'one', 'foo': 'bar', 'baz': 'three'},
{'bar': 'two', 'foo': 'bar', 'baz': 'three'},
{'bar': 'one', 'foo': 'bar', 'baz': 'four'},
{'bar': 'two', 'foo': 'bar', 'baz': 'four'}]
Patch by: Sverre Rabbelier
# Performance note: I benchmarked this code using a set instead of
# a list for the stopwords and was surprised to find that the list
# performed /better/ than the set - maybe because it's only a small
# list.
stopwords = '''
i
a
an
are
as
at
be
by
for
from
how
in
is
it
of
on
or
that
the
this
to
was
what
when
where
'''.split()
def strip_stopwords(sentence):
"Removes stopwords - also normalizes whitespace"
words = sentence.split()
sentence = []
for word in words:
if word.lower() not in stopwords:
sentence.append(word)
return u' '.join(sentence)