Refactor existing code to use the new access module
Instead of ending up with many different ways to do
access control, we end up having only one centralized
place wher access control is done.
Patch by: Sverre Rabbelier
Reviewed by: Pawel Solyga, Augie Fackler, Todd Larsen
Reviewed at: http://codereviews.googleopensourceprograms.com/1601
Review id: 1601
import os
from django.core.management.base import copy_helper, CommandError, LabelCommand
class Command(LabelCommand):
help = ("Creates a Django app directory structure for the given app name"
" in the current directory.")
args = "[appname]"
label = 'application name'
requires_model_validation = False
# Can't import settings during this command, because they haven't
# necessarily been created.
can_import_settings = False
def handle_label(self, app_name, directory=None, **options):
if directory is None:
directory = os.getcwd()
# Determine the project_name by using the basename of directory,
# which should be the full path of the project directory (or the
# current directory if no directory was passed).
project_name = os.path.basename(directory)
if app_name == project_name:
raise CommandError("You cannot create an app with the same name"
" (%r) as your project." % app_name)
copy_helper(self.style, 'app', app_name, directory, project_name)
class ProjectCommand(Command):
help = ("Creates a Django app directory structure for the given app name"
" in this project's directory.")
def __init__(self, project_directory):
super(ProjectCommand, self).__init__()
self.project_directory = project_directory
def handle_label(self, app_name, **options):
super(ProjectCommand, self).handle_label(app_name, self.project_directory, **options)