Refactor existing code to use the new access module
Instead of ending up with many different ways to do
access control, we end up having only one centralized
place wher access control is done.
Patch by: Sverre Rabbelier
Reviewed by: Pawel Solyga, Augie Fackler, Todd Larsen
Reviewed at: http://codereviews.googleopensourceprograms.com/1601
Review id: 1601
import os
import sys
from optparse import make_option, OptionParser
import django
from django.core.exceptions import ImproperlyConfigured
from django.core.management.color import color_style
class CommandError(Exception):
pass
def handle_default_options(options):
"""
Include any default options that all commands should accept
here so that ManagementUtility can handle them before searching
for user commands.
"""
if options.settings:
os.environ['DJANGO_SETTINGS_MODULE'] = options.settings
if options.pythonpath:
sys.path.insert(0, options.pythonpath)
class BaseCommand(object):
# Metadata about this command.
option_list = (
make_option('--settings',
help='The Python path to a settings module, e.g. "myproject.settings.main". If this isn\'t provided, the DJANGO_SETTINGS_MODULE environment variable will be used.'),
make_option('--pythonpath',
help='A directory to add to the Python path, e.g. "/home/djangoprojects/myproject".'),
make_option('--traceback', action='store_true',
help='Print traceback on exception'),
)
help = ''
args = ''
# Configuration shortcuts that alter various logic.
can_import_settings = True
requires_model_validation = True
output_transaction = False # Whether to wrap the output in a "BEGIN; COMMIT;"
def __init__(self):
self.style = color_style()
def get_version(self):
"""
Returns the Django version, which should be correct for all built-in
Django commands. User-supplied commands should override this method.
"""
return django.get_version()
def usage(self, subcommand):
usage = '%%prog %s [options] %s' % (subcommand, self.args)
if self.help:
return '%s\n\n%s' % (usage, self.help)
else:
return usage
def create_parser(self, prog_name, subcommand):
return OptionParser(prog=prog_name,
usage=self.usage(subcommand),
version=self.get_version(),
option_list=self.option_list)
def print_help(self, prog_name, subcommand):
parser = self.create_parser(prog_name, subcommand)
parser.print_help()
def run_from_argv(self, argv):
parser = self.create_parser(argv[0], argv[1])
options, args = parser.parse_args(argv[2:])
handle_default_options(options)
self.execute(*args, **options.__dict__)
def execute(self, *args, **options):
# Switch to English, because django-admin.py creates database content
# like permissions, and those shouldn't contain any translations.
# But only do this if we can assume we have a working settings file,
# because django.utils.translation requires settings.
if self.can_import_settings:
from django.utils import translation
translation.activate('en-us')
try:
if self.requires_model_validation:
self.validate()
output = self.handle(*args, **options)
if output:
if self.output_transaction:
# This needs to be imported here, because it relies on settings.
from django.db import connection
if connection.ops.start_transaction_sql():
print self.style.SQL_KEYWORD(connection.ops.start_transaction_sql())
print output
if self.output_transaction:
print self.style.SQL_KEYWORD("COMMIT;")
except CommandError, e:
sys.stderr.write(self.style.ERROR(str('Error: %s\n' % e)))
sys.exit(1)
def validate(self, app=None, display_num_errors=False):
"""
Validates the given app, raising CommandError for any errors.
If app is None, then this will validate all installed apps.
"""
from django.core.management.validation import get_validation_errors
try:
from cStringIO import StringIO
except ImportError:
from StringIO import StringIO
s = StringIO()
num_errors = get_validation_errors(s, app)
if num_errors:
s.seek(0)
error_text = s.read()
raise CommandError("One or more models did not validate:\n%s" % error_text)
if display_num_errors:
print "%s error%s found" % (num_errors, num_errors != 1 and 's' or '')
def handle(self, *args, **options):
raise NotImplementedError()
class AppCommand(BaseCommand):
args = '<appname appname ...>'
def handle(self, *app_labels, **options):
from django.db import models
if not app_labels:
raise CommandError('Enter at least one appname.')
try:
app_list = [models.get_app(app_label) for app_label in app_labels]
except (ImproperlyConfigured, ImportError), e:
raise CommandError("%s. Are you sure your INSTALLED_APPS setting is correct?" % e)
output = []
for app in app_list:
app_output = self.handle_app(app, **options)
if app_output:
output.append(app_output)
return '\n'.join(output)
def handle_app(self, app, **options):
raise NotImplementedError()
class LabelCommand(BaseCommand):
args = '<label label ...>'
label = 'label'
def handle(self, *labels, **options):
if not labels:
raise CommandError('Enter at least one %s.' % self.label)
output = []
for label in labels:
label_output = self.handle_label(label, **options)
if label_output:
output.append(label_output)
return '\n'.join(output)
def handle_label(self, label, **options):
raise NotImplementedError()
class NoArgsCommand(BaseCommand):
args = ''
def handle(self, *args, **options):
if args:
raise CommandError("Command doesn't accept any arguments")
return self.handle_noargs(**options)
def handle_noargs(self, **options):
raise NotImplementedError()
def copy_helper(style, app_or_project, name, directory, other_name=''):
"""
Copies either a Django application layout template or a Django project
layout template into the specified directory.
"""
# style -- A color style object (see django.core.management.color).
# app_or_project -- The string 'app' or 'project'.
# name -- The name of the application or project.
# directory -- The directory to which the layout template should be copied.
# other_name -- When copying an application layout, this should be the name
# of the project.
import re
import shutil
other = {'project': 'app', 'app': 'project'}[app_or_project]
if not re.search(r'^\w+$', name): # If it's not a valid directory name.
raise CommandError("%r is not a valid %s name. Please use only numbers, letters and underscores." % (name, app_or_project))
top_dir = os.path.join(directory, name)
try:
os.mkdir(top_dir)
except OSError, e:
raise CommandError(e)
# Determine where the app or project templates are. Use
# django.__path__[0] because we don't know into which directory
# django has been installed.
template_dir = os.path.join(django.__path__[0], 'conf', '%s_template' % app_or_project)
for d, subdirs, files in os.walk(template_dir):
relative_dir = d[len(template_dir)+1:].replace('%s_name' % app_or_project, name)
if relative_dir:
os.mkdir(os.path.join(top_dir, relative_dir))
for i, subdir in enumerate(subdirs):
if subdir.startswith('.'):
del subdirs[i]
for f in files:
if f.endswith('.pyc'):
continue
path_old = os.path.join(d, f)
path_new = os.path.join(top_dir, relative_dir, f.replace('%s_name' % app_or_project, name))
fp_old = open(path_old, 'r')
fp_new = open(path_new, 'w')
fp_new.write(fp_old.read().replace('{{ %s_name }}' % app_or_project, name).replace('{{ %s_name }}' % other, other_name))
fp_old.close()
fp_new.close()
try:
shutil.copymode(path_old, path_new)
_make_writeable(path_new)
except OSError:
sys.stderr.write(style.NOTICE("Notice: Couldn't set permission bits on %s. You're probably using an uncommon filesystem setup. No problem.\n" % path_new))
def _make_writeable(filename):
"Makes sure that the file is writeable. Useful if our source is read-only."
import stat
if sys.platform.startswith('java'):
# On Jython there is no os.access()
return
if not os.access(filename, os.W_OK):
st = os.stat(filename)
new_permissions = stat.S_IMODE(st.st_mode) | stat.S_IWUSR
os.chmod(filename, new_permissions)