Use key().name() instead of link_id
This is now possible because key_name is constructed purely from the
key fields of an entity. It is not sufficient to use just link_id,
that works only for single-scoped entities (e.g., those that either
do not have a scope, or that have a scope which itself does not have
a scope). It would break if there was an entity that has a scoped
scope (it would only include the scope's link_id in the url, which
made it impossible to look up the scope as we missed the link_id of
the scope's scope).
Patch by: Sverre Rabbelier
from django.conf.urls.defaults import *
from django.contrib.admindocs import views
urlpatterns = patterns('',
url('^$',
views.doc_index,
name='django-admindocs-docroot'
),
url('^bookmarklets/$',
views.bookmarklets,
name='django-admindocs-bookmarklets'
),
url('^tags/$',
views.template_tag_index,
name='django-admindocs-tags'
),
url('^filters/$',
views.template_filter_index,
name='django-admindocs-filters'
),
url('^views/$',
views.view_index,
name='django-admindocs-views-index'
),
url('^views/(?P<view>[^/]+)/$',
views.view_detail,
name='django-admindocs-views-detail'
),
url('^models/$',
views.model_index,
name='django-admindocs-models-index'
),
url('^models/(?P<app_label>[^\.]+)\.(?P<model_name>[^/]+)/$',
views.model_detail,
name='django-admindocs-models-detail'
),
url('^templates/(?P<template>.*)/$',
views.template_detail,
name='django-admindocs-templates'
),
)