Add tooltips style display of help_text, instead of widening the form with
another (often ridiculously large) column. Also, version the .css and .js
files so that browsers won't display the wrong cached one when we change
something.
Patch by: Dmitri Gaskin, Todd Larsen
Review by: Todd Larsen
# Python's datetime strftime doesn't handle dates before 1900.
# These classes override date and datetime to support the formatting of a date
# through its full "proleptic Gregorian" date range.
#
# Based on code submitted to comp.lang.python by Andrew Dalke
#
# >>> datetime_safe.date(1850, 8, 2).strftime("%Y/%M/%d was a %A")
# '1850/08/02 was a Friday'
from datetime import date as real_date, datetime as real_datetime
import re
import time
class date(real_date):
def strftime(self, fmt):
return strftime(self, fmt)
class datetime(real_datetime):
def strftime(self, fmt):
return strftime(self, fmt)
def combine(self, date, time):
return datetime(date.year, date.month, date.day, time.hour, time.minute, time.microsecond, time.tzinfo)
def date(self):
return date(self.year, self.month, self.day)
def new_date(d):
"Generate a safe date from a datetime.date object."
return date(d.year, d.month, d.day)
def new_datetime(d):
"""
Generate a safe datetime from a datetime.date or datetime.datetime object.
"""
kw = [d.year, d.month, d.day]
if isinstance(d, real_datetime):
kw.extend([d.hour, d.minute, d.second, d.microsecond, d.tzinfo])
return datetime(*kw)
# This library does not support strftime's "%s" or "%y" format strings.
# Allowed if there's an even number of "%"s because they are escaped.
_illegal_formatting = re.compile(r"((^|[^%])(%%)*%[sy])")
def _findall(text, substr):
# Also finds overlaps
sites = []
i = 0
while 1:
j = text.find(substr, i)
if j == -1:
break
sites.append(j)
i=j+1
return sites
def strftime(dt, fmt):
if dt.year >= 1900:
return super(type(dt), dt).strftime(fmt)
illegal_formatting = _illegal_formatting.search(fmt)
if illegal_formatting:
raise TypeError("strftime of dates before 1900 does not handle" + illegal_formatting.group(0))
year = dt.year
# For every non-leap year century, advance by
# 6 years to get into the 28-year repeat cycle
delta = 2000 - year
off = 6 * (delta // 100 + delta // 400)
year = year + off
# Move to around the year 2000
year = year + ((2000 - year) // 28) * 28
timetuple = dt.timetuple()
s1 = time.strftime(fmt, (year,) + timetuple[1:])
sites1 = _findall(s1, str(year))
s2 = time.strftime(fmt, (year+28,) + timetuple[1:])
sites2 = _findall(s2, str(year+28))
sites = []
for site in sites1:
if site in sites2:
sites.append(site)
s = s1
syear = "%4d" % (dt.year,)
for site in sites:
s = s[:site] + syear + s[site+4:]
return s