# HG changeset patch # User Puneeth Chaganti # Date 1257497931 -19800 # Node ID e072cadee389c8933b070feb80a1380532bdf178 # Parent 3c191accbb326720be53970c99fb06f29c351ea4 Minor edits to session4. diff -r 3c191accbb32 -r e072cadee389 day1/session4.tex --- a/day1/session4.tex Fri Nov 06 13:53:20 2009 +0530 +++ b/day1/session4.tex Fri Nov 06 14:28:51 2009 +0530 @@ -74,7 +74,7 @@ %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% % Title page -\title[Matrices \& Equations]{Python for Science and Engg: Matrices, Least Square Fit, \& Solution of equations} +\title[Matrices \& Curve Fitting]{Python for Science and Engg: Matrices \& Least Square Fit} \author[FOSSEE] {FOSSEE} @@ -277,7 +277,7 @@ \end{frame} \begin{frame}[fragile] - \frametitle{Slicing \& Striding Exercises \ldots} + \frametitle{Solutions} \begin{small} \begin{lstlisting} In []: imshow(A[:256,:256]) @@ -462,8 +462,7 @@ \frametitle{\typ{lstsq}} \begin{itemize} \item We need to fit a line through points for the equation $T^2 = m \cdot L+c$ -\item The equation can be re-written as $T^2 = A \cdot p$ -\item where A is +\item In matrix form, the equation can be represented as $T^2 = A \cdot p$, where A is $\begin{bmatrix} L_1 & 1 \\ L_2 & 1 \\ @@ -536,13 +535,22 @@ \end{lstlisting} \end{frame} +\begin{frame}[fragile] +\frametitle{Least Squares Fit} +\vspace{-0.15in} +\begin{figure} +\includegraphics[width=4in]{data/least-sq-fit} +\end{figure} +\end{frame} + \section{Summary} \begin{frame} - \frametitle{What did we learn??} + \frametitle{What did we learn?} \begin{itemize} \item Matrices \begin{itemize} \item Accessing elements + \item Slicing and Striding \item Transpose \item Addition \item Multiplication