Modified cheat sheet of session 1 day 2.
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%Tutorial slides on Python.
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% Author: FOSSEE
% Copyright (c) 2009, FOSSEE, IIT Bombay
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% Title page
\title[Matrices \& Curve Fitting]{Python for Science and Engg: Matrices \& Least Square Fit}
\author[FOSSEE] {FOSSEE}
\institute[IIT Bombay] {Department of Aerospace Engineering\\IIT Bombay}
\date[] {7 November, 2009\\Day 1, Session 4}
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\begin{frame}<beamer>
\frametitle{Outline}
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\begin{document}
\begin{frame}
\titlepage
\end{frame}
\begin{frame}
\frametitle{Outline}
\tableofcontents
% \pausesections
\end{frame}
\section{Matrices}
\begin{frame}
\frametitle{Matrices: Introduction}
\alert{All matrix operations are done using \kwrd{arrays}}
\end{frame}
\begin{frame}[fragile]
\frametitle{Matrices: Initializing}
\begin{lstlisting}
In []: A = array([[ 1, 1, 2, -1],
[ 2, 5, -1, -9],
[ 2, 1, -1, 3],
[ 1, -3, 2, 7]])
In []: A
Out[]:
array([[ 1, 1, 2, -1],
[ 2, 5, -1, -9],
[ 2, 1, -1, 3],
[ 1, -3, 2, 7]])
\end{lstlisting}
\end{frame}
\begin{frame}[fragile]
\frametitle{Initializing some special matrices}
\begin{small}
\begin{lstlisting}
In []: ones((3,5))
Out[]:
array([[ 1., 1., 1., 1., 1.],
[ 1., 1., 1., 1., 1.],
[ 1., 1., 1., 1., 1.]])
In []: ones_like([1, 2, 3, 4, 5])
Out[]: array([1, 1, 1, 1, 1])
In []: identity(2)
Out[]:
array([[ 1., 0.],
[ 0., 1.]])
\end{lstlisting}
Also available \alert{\typ{zeros, zeros_like, empty, empty_like}}
\end{small}
\end{frame}
\begin{frame}[fragile]
\frametitle{Accessing elements}
\begin{lstlisting}
In []: C = array([[1,1,2],
[2,4,1],
[-1,3,7]])
In []: C[1][2]
Out[]: 1
In []: C[1,2]
Out[]: 1
In []: C[1]
Out[]: array([2, 4, 1])
\end{lstlisting}
\end{frame}
\begin{frame}[fragile]
\frametitle{Changing elements}
\begin{small}
\begin{lstlisting}
In []: C[1,1] = -2
In []: C
Out[]:
array([[ 1, 1, 2],
[ 2, -2, 1],
[-1, 3, 7]])
In []: C[1] = [0,0,0]
In []: C
Out[]:
array([[ 1, 1, 2],
[ 0, 0, 0],
[-1, 3, 7]])
\end{lstlisting}
\end{small}
How to change one \alert{column}?
\end{frame}
\begin{frame}[fragile]
\frametitle{Slicing}
\begin{small}
\begin{lstlisting}
In []: C[:,1]
Out[]: array([1, 0, 3])
In []: C[1,:]
Out[]: array([0, 0, 0])
In []: C[0:2,:]
Out[]:
array([[1, 1, 2],
[0, 0, 0]])
In []: C[1:3,:]
Out[]:
array([[ 0, 0, 0],
[-1, 3, 7]])
\end{lstlisting}
\end{small}
\end{frame}
\begin{frame}[fragile]
\frametitle{Slicing \ldots}
\begin{small}
\begin{lstlisting}
In []: C[:2,:]
Out[]:
array([[1, 1, 2],
[0, 0, 0]])
In []: C[1:,:]
Out[]:
array([[ 0, 0, 0],
[-1, 3, 7]])
In []: C[1:,:2]
Out[]:
array([[ 0, 0],
[-1, 3]])
\end{lstlisting}
\end{small}
\end{frame}
\begin{frame}[fragile]
\frametitle{Striding}
\begin{small}
\begin{lstlisting}
In []: C[::2,:]
Out[]:
array([[ 1, 1, 2],
[-1, 3, 7]])
In []: C[:,::2]
Out[]:
xarray([[ 1, 2],
[ 0, 0],
[-1, 7]])
In []: C[::2,::2]
Out[]:
array([[ 1, 2],
[-1, 7]])
\end{lstlisting}
\end{small}
\end{frame}
\begin{frame}[fragile]
\frametitle{Slicing \& Striding Exercises}
\begin{small}
\begin{lstlisting}
In []: A = imread('lena.png')
In []: imshow(A)
Out[]: <matplotlib.image.AxesImage object at 0xa0384cc>
In []: A.shape
Out[]: (512, 512, 4)
\end{lstlisting}
\end{small}
\begin{itemize}
\item Crop the image to get the top-left quarter
\item Crop the image to get only the face
\item Resize image to half by dropping alternate pixels
\end{itemize}
\end{frame}
\begin{frame}[fragile]
\frametitle{Solutions}
\begin{small}
\begin{lstlisting}
In []: imshow(A[:256,:256])
Out[]: <matplotlib.image.AxesImage object at 0xb6f658c>
In []: imshow(A[200:400,200:400])
Out[]: <matplotlib.image.AxesImage object at 0xb757c2c>
In []: imshow(A[::2,::2])
Out[]: <matplotlib.image.AxesImage object at 0xb765c8c>
\end{lstlisting}
\end{small}
\end{frame}
\begin{frame}[fragile]
\frametitle{Transpose of a Matrix}
\begin{lstlisting}
In []: A.T
Out[]:
array([[ 1, 2, 2, 1],
[ 1, 5, 1, -3],
[ 2, -1, -1, 2],
[-1, -9, 3, 7]])
\end{lstlisting}
\end{frame}
\begin{frame}[fragile]
\frametitle{Sum of all elements}
\begin{lstlisting}
In []: sum(A)
Out[]: 12
\end{lstlisting}
\end{frame}
\begin{frame}[fragile]
\frametitle{Matrix Addition}
\begin{lstlisting}
In []: B = array([[3,2,-1,5],
[2,-2,4,9],
[-1,0.5,-1,-7],
[9,-5,7,3]])
In []: A + B
Out[]:
array([[ 4. , 3. , 1. , 4. ],
[ 4. , 3. , 3. , 0. ],
[ 1. , 1.5, -2. , -4. ],
[ 10. , -8. , 9. , 10. ]])
\end{lstlisting}
\end{frame}
\begin{frame}[fragile]
\frametitle{Elementwise Multiplication}
\begin{lstlisting}
In []: A*B
Out[]:
array([[ 3. , 2. , -2. , -5. ],
[ 4. , -10. , -4. , -81. ],
[ -2. , 0.5, 1. , -21. ],
[ 9. , 15. , 14. , 21. ]])
\end{lstlisting}
\end{frame}
\begin{frame}[fragile]
\frametitle{Matrix Multiplication}
\begin{lstlisting}
In []: dot(A,B)
Out[]:
array([[ -6. , 6. , -6. , -3. ],
[-64. , 38.5, -44. , 35. ],
[ 36. , -13.5, 24. , 35. ],
[ 58. , -26. , 34. , -15. ]])
\end{lstlisting}
\end{frame}
\begin{frame}[fragile]
\frametitle{Inverse of a Matrix}
\begin{lstlisting}
In []: inv(A)
\end{lstlisting}
\begin{small}
\begin{lstlisting}
Out[]:
array([[-0.5 , 0.55, -0.15, 0.7 ],
[ 0.75, -0.5 , 0.5 , -0.75],
[ 0.5 , -0.15, -0.05, -0.1 ],
[ 0.25, -0.25, 0.25, -0.25]])
\end{lstlisting}
\end{small}
\end{frame}
\begin{frame}[fragile]
\frametitle{Determinant}
\begin{lstlisting}
In []: det(A)
Out[]: 80.0
\end{lstlisting}
\end{frame}
%%use S=array(X,Y)
\begin{frame}[fragile]
\frametitle{Eigenvalues and Eigen Vectors}
\begin{small}
\begin{lstlisting}
In []: E = array([[3,2,4],[2,0,2],[4,2,3]])
In []: eig(E)
Out[]:
(array([-1., 8., -1.]),
array([[-0.74535599, 0.66666667, -0.1931126 ],
[ 0.2981424 , 0.33333333, -0.78664085],
[ 0.59628479, 0.66666667, 0.58643303]]))
In []: eigvals(E)
Out[]: array([-1., 8., -1.])
\end{lstlisting}
\end{small}
\end{frame}
%% \begin{frame}[fragile]
%% \frametitle{Computing Norms}
%% \begin{lstlisting}
%% In []: norm(E)
%% Out[]: 8.1240384046359608
%% \end{lstlisting}
%% \end{frame}
%% \begin{frame}[fragile]
%% \frametitle{Singular Value Decomposition}
%% \begin{small}
%% \begin{lstlisting}
%% In []: svd(E)
%% Out[]:
%% (array(
%% [[ -6.66666667e-01, -1.23702565e-16, 7.45355992e-01],
%% [ -3.33333333e-01, -8.94427191e-01, -2.98142397e-01],
%% [ -6.66666667e-01, 4.47213595e-01, -5.96284794e-01]]),
%% array([ 8., 1., 1.]),
%% array([[-0.66666667, -0.33333333, -0.66666667],
%% [-0. , 0.89442719, -0.4472136 ],
%% [-0.74535599, 0.2981424 , 0.59628479]]))
%% \end{lstlisting}
%% \end{small}
%% \inctime{15}
%% \end{frame}
\section{Least Squares Fit}
\begin{frame}[fragile]
\frametitle{$L$ vs. $T^2$ - Scatter}
\vspace{-0.15in}
\begin{figure}
\includegraphics[width=4in]{data/L-Tsq-points}
\end{figure}
\end{frame}
\begin{frame}[fragile]
\frametitle{$L$ vs. $T^2$ - Line}
\vspace{-0.15in}
\begin{figure}
\includegraphics[width=4in]{data/L-Tsq-Line}
\end{figure}
\end{frame}
\begin{frame}[fragile]
\frametitle{$L$ vs. $T^2$ }
\frametitle{$L$ vs. $T^2$ - Least Square Fit}
\vspace{-0.15in}
\begin{figure}
\includegraphics[width=4in]{data/least-sq-fit}
\end{figure}
\end{frame}
\begin{frame}
\frametitle{Least Square Fit Curve}
\begin{itemize}
\item $T^2$ and $L$ have a linear relationship
\item Hence, Least Square Fit Curve is a line
\item we shall use the \typ{lstsq} function
\end{itemize}
\end{frame}
\begin{frame}[fragile]
\frametitle{\typ{lstsq}}
\begin{itemize}
\item We need to fit a line through points for the equation $T^2 = m \cdot L+c$
\item In matrix form, the equation can be represented as $T^2 = A \cdot p$, where A is
$\begin{bmatrix}
L_1 & 1 \\
L_2 & 1 \\
\vdots & \vdots\\
L_N & 1 \\
\end{bmatrix}$
and p is
$\begin{bmatrix}
m\\
c\\
\end{bmatrix}$
\item We need to find $p$ to plot the line
\end{itemize}
\end{frame}
\begin{frame}[fragile]
\frametitle{Getting $L$ and $T^2$}
If you \alert{closed} IPython after session 2
\begin{lstlisting}
In []: l = []
In []: t = []
In []: for line in open('pendulum.txt'):
.... point = line.split()
.... l.append(float(point[0]))
.... t.append(float(point[1]))
....
....
\end{lstlisting}
\end{frame}
\begin{frame}[fragile]
\frametitle{Generating $A$}
\begin{lstlisting}
In []: A = array([l, ones_like(l)])
In []: A = A.T
\end{lstlisting}
%% \begin{itemize}
%% \item A is also called a Van der Monde matrix
%% \item It can also be generated using \typ{vander}
%% \end{itemize}
%% \begin{lstlisting}
%% In []: A = vander(L, 2)
%% \end{lstlisting}
\end{frame}
\begin{frame}[fragile]
\frametitle{\typ{lstsq} \ldots}
\begin{itemize}
\item Now use the \typ{lstsq} function
\item Along with a lot of things, it returns the least squares solution
\end{itemize}
\begin{lstlisting}
In []: result = lstsq(A,TSq)
In []: coef = result[0]
\end{lstlisting}
\end{frame}
\begin{frame}[fragile]
\frametitle{Least Square Fit Line \ldots}
We get the points of the line from \typ{coef}
\begin{lstlisting}
In []: Tline = coef[0]*l + coef[1]
\end{lstlisting}
\begin{itemize}
\item Now plot \typ{Tline} vs. \typ{l}, to get the Least squares fit line.
\end{itemize}
\begin{lstlisting}
In []: plot(l, Tline)
\end{lstlisting}
\end{frame}
\begin{frame}[fragile]
\frametitle{Least Squares Fit}
\vspace{-0.15in}
\begin{figure}
\includegraphics[width=4in]{data/least-sq-fit}
\end{figure}
\end{frame}
\section{Summary}
\begin{frame}
\frametitle{What did we learn?}
\begin{itemize}
\item Matrices
\begin{itemize}
\item Initializing
\item Accessing elements
\item Slicing and Striding
\item Transpose
\item Addition
\item Multiplication
\item Inverse of a matrix
\item Determinant
\item Eigenvalues and Eigen vector
%% \item Norms
%% \item Singular Value Decomposition
\end{itemize}
\item Least Square Curve fitting
\end{itemize}
\end{frame}
\end{document}