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%Tutorial slides on Python.
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% Author: FOSSEE
% Copyright (c) 2009, FOSSEE, IIT Bombay
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% Title page
\title[Statistics]{Python for Science and Engg. Statistics}

\author[FOSSEE] {FOSSEE}

\institute[IIT Bombay] {Department of Aerospace Engineering\\IIT Bombay}
\date[] {31, October 2009\\Day 1, Session 3}
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%% the beginning of each subsection:
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    \frametitle{Outline}
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\begin{document}

\begin{frame}
  \maketitle
\end{frame}

%% \begin{frame}
%%   \frametitle{Outline}
%%   \tableofcontents
%%   % You might wish to add the option [pausesections]
%% \end{frame}

\begin{frame}
  \frametitle{More on data processing}
  \begin{block}{}
    We have a huge--1m records--data file.\\How do we do \emph{efficient} statistical computations, that is find mean, median, mode, standard deveiation etc; draw pie charts?
  \end{block}
\end{frame}


\begin{frame}
  \frametitle{Statistical Analysis and Parsing}
  Read the data supplied in \emph{sslc1.txt} and obtain the following statistics:
  \begin{itemize}
    \item Draw a pie chart representing the number of students who scored more than 90\% in Science per region.
    \item Draw a pie chart representing the number of students who scored more than 90\% per subject(All regions combined).
    \item Print mean, median, mode and standard deviation of math scores for all regions combined.
  \end{itemize}
\end{frame}

\begin{frame}
  \frametitle{Statistical Analysis and Parsing \ldots}
  Machinery Required -
  \begin{itemize}
    \item File reading
    \item Parsing
    \item Dictionaries
    \item NumPy arrays
    \item Statistical operations
  \end{itemize}
\end{frame}

\begin{frame}
  \frametitle{File reading and parsing}
  Understanding the structure of sslc1.txt
  \begin{itemize}
    \item Each line in the file corresponds to one student's details
    \item aka record
    \item Each record consists of several fields separated by a ';'
  \end{itemize}
\end{frame}

\begin{frame}
  \frametitle{File reading and parsing \ldots}
  Each record consists of:
  \begin{itemize}
    \item Region Code
    \item Roll Number
    \item Name
    \item Marks of 5 subjects: English, Hindi, Maths, Science, Social
    \item Total marks
    \item Pass/Fail (P/F)
    \item Withdrawn (W)
  \end{itemize}
\end{frame}

\begin{frame}[fragile]
  \frametitle{File reading and parsing \ldots}
  \begin{lstlisting}
for record in open('sslc1.txt'):
    fields = record.split(';')
  \end{lstlisting}
\end{frame}

\begin{frame}[fragile]
  \frametitle{Dictionary: Introduction}
  \begin{itemize}
    \item lists index: 0 \ldots n
    \item dictionaries index using strings
  \end{itemize}
\begin{block}{Example}
d = \{ ``Hitchhiker's guide'' : 42,
     ``Terminator'' : ``I'll be back''\}\\
d[``Terminator''] => ``I'll be back''
\end{block}
\end{frame}

\begin{frame}[fragile]
  \frametitle{Dictionary: Introduction}
\begin{lstlisting}
In [1]: d = {"Hitchhiker's guide" : 42,
      "Terminator" : "I'll be back"}

In [2]: d["Hitchhiker's guide"]
Out[2]: 42

In [3]: "Hitchhiker's guide" in d
Out[3]: True

In [4]: "Guido" in d
Out[4]: False
\end{lstlisting}
\end{frame}

\begin{frame}[fragile]
  \frametitle{Dictionary: Introduction}
\begin{lstlisting}
In [5]: d.keys()
Out[5]: ['Terminator', "Hitchhiker's 
                              guide"]

In [6]: d.values()
Out[6]: ["I'll be back", 42]
\end{lstlisting}
\end{frame}

\begin{frame}[fragile]
  \frametitle{enumerate: Iterating through list indices}
\begin{lstlisting}
In [1]: names = ["Guido","Alex", "Tim"]

In [2]: for i, name in enumerate(names):
   ...:     print i, name
   ...: 
0 Guido
1 Alex
2 Tim
\end{lstlisting}
\end{frame}

\begin{frame}[fragile]
  \frametitle{Dictionary: Building parsed data}
    Let our dictionary be:
    \begin{lstlisting}
science = {} # is an empty dictionary
    \end{lstlisting}
\end{frame}

\begin{frame}[fragile]
  \frametitle{Dictionary - Building parsed data}
  \begin{itemize}
    \item \emph{Keys} of \emph{science} will be region codes
    \item Value of a \emph{science} will be the number students who scored more than 90\% in that region
  \end{itemize}
\end{frame}

\begin{frame}[fragile]
  \frametitle{Building parsed data \ldots}
  \begin{lstlisting}
from pylab import pie

science = {}

for record in open('sslc1.txt'):
    record = record.strip()
    fields = record.split(';')

    region_code = fields[0].strip()
  \end{lstlisting}
\end{frame}

\begin{frame}[fragile]
  \frametitle{Building parsed data \ldots}
  \begin{lstlisting}
if region_code not in science:
    science[region_code] = 0

score_str = fields[4].strip()

score = int(score_str) if
    score_str != 'AA' else 0

if score > 90:
    science[region_code] += 1
  \end{lstlisting}
\end{frame}

\begin{frame}[fragile]
  \frametitle{Pie charts}
  \small
  \begin{lstlisting}
figure(1)
pie(science.values(), 
    labels=science.keys())
title('Students scoring 90% and above 
      in science by region')
savefig('/tmp/science.png')
  \end{lstlisting}
\begin{columns}
    \column{5.25\textwidth}
    \hspace*{1.1in}
\includegraphics[height=2in, interpolate=true]{data/science}
    \column{0.8\textwidth}
\end{columns}
\end{frame}

\begin{frame}[fragile]
  \frametitle{Building data for all subjects \ldots}
  \begin{lstlisting}
from pylab import pie
from scipy import mean, median, std
from scipy import stats

scores = [[]] * 5
ninety_percents = [{}] * 5
  \end{lstlisting}
\end{frame}

\begin{frame}[fragile]
  \frametitle{Building data for all subjects \ldots}
  \begin{lstlisting}
from pylab import pie
from scipy import mean, median, std
from scipy import stats
  \end{lstlisting}

  \begin{block}{Repeating list items}
    \begin{lstlisting}
scores = [[]] * 5
ninety_percents = [{}] * 5
    \end{lstlisting}
  \end{block}
\end{frame}

\begin{frame}[fragile]
  \frametitle{Building data for all subjects \ldots}
  \begin{lstlisting}
for record in open('sslc1.txt'):
    record = record.strip()
    fields = record.split(';')

    region_code = fields[0].strip()
  \end{lstlisting}
\end{frame}

\begin{frame}[fragile]
  \frametitle{Building data for all subjects \ldots}
  \small
  \begin{lstlisting}
for i, field in enumerate(fields[3:8]):
    if region_code not in ninety_percents[i]:
        ninety_percents[i][region_code] = 0

    score_str = field.strip()
    score = int(score_str) if
      score_str != 'AA' else 0

    scores[i].append(score)

    if score > 90:
        ninety_percents[i][region_code] += 1
  \end{lstlisting}
\end{frame}

\begin{frame}[fragile]
  \frametitle{Consolidating data}
  \begin{lstlisting}
subj_total = []
for subject in ninety_percents:
    subj_total.append(sum(
         subject.values()))
  \end{lstlisting}
\end{frame}

\begin{frame}[fragile]
  \frametitle{Pie charts}
  \begin{lstlisting}
figure(2)
pie(subj_total, labels=['English',
    'Hindi', 'Maths', 'Science',
    'Social'])
title('Students scoring more than
      90% by subject(All regions
      combined).')
savefig('/tmp/all_regions.png')
  \end{lstlisting}
\end{frame}

\begin{frame}[fragile]
  \frametitle{Pie charts}
  \includegraphics[height=3in, interpolate=true]{data/all_regions}
\end{frame}

\begin{frame}
\frametitle{L vs $T^2$ \ldots}
Let's go back to the L vs $T^2$ plot
\begin{itemize}
\item We first look at obtaining $T^2$ from T
\item Then, we look at plotting a Least Squares fit
\end{itemize}
\end{frame}

\begin{frame}[fragile]
  \frametitle{Obtaining statistics}
  \begin{lstlisting}
math_scores = array(scores[2])

print "Mean: ", mean(math_scores)

print "Median: ", median(math_scores)

print "Mode: ", stats.mode(math_scores)

print "Standard Deviation: ",
              std(math_scores)
  \end{lstlisting}
\end{frame}

\begin{frame}[fragile]
  \frametitle{What tools did we use?}
  \begin{itemize}
   \item Dictionaries for storing data
   \item Facilities for drawing pie charts
   \item NumPy arrays for efficient array manipulations
   \item Functions for statistical computations - mean, median, mode, standard deviation
  \end{itemize}
\end{frame}

\begin{frame}[fragile]
\frametitle{Dealing with data whole-sale}
\begin{lstlisting}
In []: for t in T:
 ....:     TSq.append(t*t)
\end{lstlisting}
\begin{itemize}
\item This is not very efficient
\item We are squaring element after element
\item We use arrays to make this efficient
\end{itemize}
\begin{lstlisting}
In []: L = array(L)
In []: T = array(T)
In []: TSq = T*T
\end{lstlisting}
\end{frame}

\begin{frame}[fragile]
\frametitle{Arrays}
\begin{itemize}
\item \typ{T} and \typ{L} are now arrays
\item arrays are very efficient and powerful 
\item Very easy to perform element-wise operations
\item \typ{+, -, *, /, \%}
\item More about arrays later
\end{itemize}
\end{frame}

\begin{frame}[fragile]
\frametitle{Least Squares Fit}
\vspace{-0.15in}
\begin{figure}
\includegraphics[width=4in]{data/L-Tsq-Line.png}
\end{figure}
\end{frame}

\begin{frame}[fragile]
\frametitle{Least Squares Fit}
\vspace{-0.15in}
\begin{figure}
\includegraphics[width=4in]{data/least-sq-fit.png}
\end{figure}
\end{frame}

\begin{frame}
\frametitle{Least Square Fit Curve}
\begin{itemize}
\item $T^2$ and $L$ have a linear relationship
\item Hence, Least Square Fit Curve is a line
\item we shall use the \typ{lstsq} function
\end{itemize}
\end{frame}

\begin{frame}[fragile]
\frametitle{\typ{lstsq}}
\begin{itemize}
\item We need to fit a line through points for the equation $T^2 = m \cdot L+c$
\item The equation can be re-written as $T^2 = A \cdot p$
\item where A is   
  $\begin{bmatrix}
  L_1 & 1 \\
  L_2 & 1 \\
  \vdots & \vdots\\
  L_N & 1 \\
  \end{bmatrix}$
  and p is 
  $\begin{bmatrix}
  m\\
  c\\
  \end{bmatrix}$
\item We need to find $p$ to plot the line
\end{itemize}
\end{frame}

\begin{frame}[fragile]
\frametitle{Van der Monde Matrix}
\begin{itemize}
\item A is also called a Van der Monde matrix
\item It can be generated using \typ{vander}
\end{itemize}
Van der Monde matrix of order M
\begin{equation*}
  \begin{bmatrix}
  l_1^{M-1} & \ldots & l_1 & 1 \\
  l_2^{M-1} & \ldots &l_2 & 1 \\
  \vdots & \ldots & \vdots & \vdots\\
  l_N^{M-1} & \ldots & l_N & 1 \\
  \end{bmatrix}
\end{equation*}
\begin{lstlisting}
In []: A = vander(L,2)
\end{lstlisting}
\end{frame}

\begin{frame}[fragile]
\frametitle{\typ{lstsq} \ldots}
\begin{itemize}
\item Now use the \typ{lstsq} function
\item Along with a lot of things, it returns the least squares solution
\end{itemize}
\begin{lstlisting}
In []: coef, res, r, s = lstsq(A,TSq)
\end{lstlisting}
\end{frame}

\begin{frame}[fragile]
\frametitle{Least Square Fit Line \ldots}
We get the points of the line from \typ{coef}
\begin{lstlisting}
In []: Tline = coef[0]*L + coef[1]
\end{lstlisting}
\begin{itemize}
\item Now plot Tline vs. L, to get the Least squares fit line. 
\end{itemize}
\begin{lstlisting}
In []: plot(L, Tline)
\end{lstlisting}
\end{frame}

\end{document}
