Split the list view code up in three pieces
1. getListContents which returns the required contents dictionary
2. _list which returns the response for a specified list of contents
3. list which constructs just one content dict and passes it to _list
This way it is easier to do step 1 and 2 in other code than list(),
which makes it possible to display multiple list pages (by calling
getListContents multiple times and passing the result to _list).
from django.core.management.base import BaseCommand
class Command(BaseCommand):
help = "Runs this project as a FastCGI application. Requires flup."
args = '[various KEY=val options, use `runfcgi help` for help]'
def handle(self, *args, **options):
from django.conf import settings
from django.utils import translation
# Activate the current language, because it won't get activated later.
try:
translation.activate(settings.LANGUAGE_CODE)
except AttributeError:
pass
from django.core.servers.fastcgi import runfastcgi
runfastcgi(args)
def usage(self, subcommand):
from django.core.servers.fastcgi import FASTCGI_HELP
return FASTCGI_HELP