Refactor existing code to use the new access module
Instead of ending up with many different ways to do
access control, we end up having only one centralized
place wher access control is done.
Patch by: Sverre Rabbelier
Reviewed by: Pawel Solyga, Augie Fackler, Todd Larsen
Reviewed at: http://codereviews.googleopensourceprograms.com/1601
Review id: 1601
from django.core.management.base import copy_helper, CommandError, LabelCommand
import os
import re
from random import choice
INVALID_PROJECT_NAMES = ('django', 'site', 'test')
class Command(LabelCommand):
help = "Creates a Django project directory structure for the given project name in the current directory."
args = "[projectname]"
label = 'project name'
requires_model_validation = False
# Can't import settings during this command, because they haven't
# necessarily been created.
can_import_settings = False
def handle_label(self, project_name, **options):
# Determine the project_name a bit naively -- by looking at the name of
# the parent directory.
directory = os.getcwd()
try:
proj_name = __import__(project_name)
if proj_name:
raise CommandError("%r conflicts with the name of an existing Python module and cannot be used as a project name. Please try another name." % project_name)
except ImportError:
if project_name in INVALID_PROJECT_NAMES:
raise CommandError("%r contains an invalid project name. Please try another name." % project_name)
copy_helper(self.style, 'project', project_name, directory)
# Create a random SECRET_KEY hash, and put it in the main settings.
main_settings_file = os.path.join(directory, project_name, 'settings.py')
settings_contents = open(main_settings_file, 'r').read()
fp = open(main_settings_file, 'w')
secret_key = ''.join([choice('abcdefghijklmnopqrstuvwxyz0123456789!@#$%^&*(-_=+)') for i in range(50)])
settings_contents = re.sub(r"(?<=SECRET_KEY = ')'", secret_key + "'", settings_contents)
fp.write(settings_contents)
fp.close()